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earnstyle [38]
3 years ago
11

Help plz is due today?!!!!

Biology
2 answers:
Fudgin [204]3 years ago
7 0

Answer:

A. Large fins

Explanation:

Having large fins help the fish to become faster and to be fast in general underwater.

Mama L [17]3 years ago
4 0

Answer:

A: Large fins

Explanation:

Large fins help it propell through the ocean fast.

You might be interested in
The number of ducks in a pond is equal to the square root of the number of fish, and the number of turtles is equal to the cube
brilliants [131]

Answer:

There are 64 fish, 8 ducks and 4 turtles.

Explanation:

From the question, there can be from 2 to 99 fish in the pond. However, there cannot be fractions in the number of fish, ducks or turtles. Hence, the number of fish must have both of a perfect square and perfect cube. The perfect squares from 2 to 99 are 4, 9, 16, 25, 36, 49, 64 and 81. The perfect cubes from 2 to 99 are 8, 27 and 64. Since only 64 fits both criteria, the number of fish is 64. The number of ducks is the square root of number of fish, which is the square root of 64. The square root of 64 can be either positive 8 or negative 8. However, there cannot be negative numbers, so there are 8 ducks in total. The number of turtles is the cube root of the number of fish, which is the cube root of 64 and it is 4.

7 0
2 years ago
Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
3 years ago
The most common location of surgically treatable arteriosclerotic disease causing tias is the:
expeople1 [14]
Um can u plz be specific 
7 0
2 years ago
Use the paragraph to answer the question. A team of biologists has been investigating fireflies to determine the cause of their
konstantin123 [22]

Explanation:

Biologists have discovered that the reason behind the decline of fireflies is habitat loss, light pollution and excessive light; excessive light can disrupt the insects mating ritual.

3 0
3 years ago
1)What is the importance of conjugation?
DaniilM [7]

Answer:

evolution of bacterial genomes.

Explanation:

Conjugation plays an important role in evolution of evolution of bacterial genomes.Human pathogenic bacteria may have acquired many of the virulent traits, as well as antibiotic resistance by conjugation.

6 0
2 years ago
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