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3 years ago

What is the distance between point A and point B?what is the ordered pair for each of the points plotted above?

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

6 0

Answer:

A: (0,0), B: (3, -4), 5 units

Step-by-step explanation:

A: (0,0), B: (3, -4)

To find the distance, use the distance formula. Square-root((0-3)^2+(0-(-4))^2) ---> Square-root((-3)^2 + 4^2) ---> Square-root(9+16) ---> Square-root(25) ---> 5units.

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Which of the following shapes are rhombuses ? Please choose 2 correct answers !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Gemiola [76]

The answers are C and B

5 0

3 years ago

What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?

notsponge [240]

$x^2+bx+c$ will have real roots when the discriminant of the quadratic, $\Delta=b^2-4c$ , is non-negative, i.e.

$b^2-4c\ge0\implies b^2\ge4c$

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking $b,c$ at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both $b,c$ are chosen indepently of one another from [0, 1]. Let $B,C$ denote the random variables that take on the values of $b,c$ , respectively. I'll assume $B,C$ are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

$f_X(x)=\begin{cases}1&\text{for }0$

$F_X(x)=\begin{cases}0&\text{for }x$

where $X$ is either of $B,C$ .

Then the question is to find $P(B^2\ge4C)$ . We have

$P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)$

and we can condition the random variable $C$ on the event of $B=b$ by supposing

$P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)$

then integrate over all possible values of $b$ .

$=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db$

$=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db$

$=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}$

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3 years ago

Janet, an experienced shipping clerk, can fill a certain order in 2 hours. Tom, a new clerk, needs 3 hours to do the same job.

Arte-miy333 [17]

Answer:

1 hour and 15 minutes.

Step-by-step explanation:

Since Janet, an experienced shipping clerk, can fill a certain order in 2 hours, while Tom, a new clerk, needs 3 hours to do the same job, to determine how long will it take them to fill the order by working together you must perform the following logical reasoning:

Each of them will do half the work, so in principle, Janet will do her work in 1 hour, while Tom will do it in 1 hour and a half. Now, the remaining half hour that Tom has more than Janet can in turn be divided in two, with which each one will do their work in 15 minutes. Thus, the order will be ready in 1 hour and 15 minutes.

8 0

3 years ago

Divide. Write your answer as a fraction in simplest form.<br><br> −7/10÷ 2/5= help

WARRIOR [948]

Answer:

- $\frac{7}{4}$

Step-by-step explanation:

Given

- $\frac{7}{10}$ ÷ $\frac{2}{5}$

Leave the first fraction

Change division to multiplication

Turn the second fraction upside down

= - $\frac{7}{10}$ × $\frac{5}{2}$ ← cancel 5 and 10 by 5

= - $\frac{7}{2}$ × $\frac{1}{2}$

= - $\frac{7(1)}{2(2)}$

= - $\frac{7}{4}$

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3 years ago

One package of tile will cover 3 square feet.How many packages will shee need 8,13,15,39

IrinaVladis [17]

Hey there! :)

Answer:

13 packages.

Step-by-step explanation:

Begin by finding the total area of this composite figure. Separate the figure into separate rectangles. Use the formula A = l × w to calculate the area of each:

Smaller rectangle:

Subtract 7 from 9 to find the width:

9 -7 = 2. Therefore:

2 × 2 = 4 ft².

Larger rectangle:

7 × 5 = 35 ft².

Add up the two areas to find the area of the entire figure:

4 + 35 = 39 ft².

If each package of tile covers 3 ft², simply divide to find the package of tiles needed:

39 / 3 = 13 packages.

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4 years ago