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3 years ago

5

3) Express the left side as a square: x - 4x+1=0

1 answer:

salantis [7]3 years ago

8 0

Answer:

work it step btmy step i dont kno the answer

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A rectangular painting measures 15 inches by 18 inches and contains a frame of uniform width around the four edges. The perimete

vfiekz [6]

Answer:

3 inches

Step-by-step explanation:

Lenght = 18 inches

Width =15 inches

Perimeter of the rectangular painting and frame = 90 inches

Let X be the width of the frame

The width of the framed picture = 15 + 2x

The length of the framed picture = 18 + 2x

Perimeter = 2 (L + W)

90 = 2(15 + 2x + 18+ 2x)

90 = 2(33 + 4x)

90 = 66 + 8x

8x = 90 - 66

8x = 24

x = 24/8

x = 3 inches

the width of the frame is 3 inches

5 0

3 years ago

Y-4x=3. 2x-3y=21 can someone help

mars1129 [50]

Y-4X =3 ; 2x-3y=21

Y= 3+ 4x

2x -3( 3+4x)= 21

2x- 9- 12x= 21

-10x -9= 21

-10x -9+9= 21+9

-10x = 30

X= 30/-10= -3

Y= 3+4x = 3+ 4* (-3)= 3-12= -9

3 0

3 years ago

Solve the following triangle. Given A=51 degrees b=40 c=45

STALIN [3.7K]

Answer:

$a=36.87\ units$

$B=57.47^o$

$C=71.53^o$

Step-by-step explanation:

step 1

Find the length side a

Applying the law of cosines

$a^2=b^2+c^2-2(b)(c)cos(A)$

substitute the given values

$a^2=40^2+45^2-2(40)(45)cos(51^o)$

$a^2=1,359.4466$

$a=36.87\ units$

step 2

Find the measure of angle B

Applying the law of sines

$\frac{a}{sin(A)} =\frac{b}{sin(B)}$

substitute the given values

$\frac{36.87}{sin(51^o)} =\frac{40}{sin(B)}$

$sin(B)=\frac{sin(51^o)}{36.87}{40}$

$B=sin^{-1}(\frac{sin(51^o)}{36.87}{40})=57.47^o$

step 3

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

substitute the given values

$51^o+57.47^o+C=180^o$

$108.47^o+C=180^o$

$C=180^o-108.47^o=71.53^o$

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3 years ago

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zaharov [31]

Tell Me if I'm Wrong But I Believe It's 198m3

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2 years ago

explain how I determined the answer to number 3 on the assignment today and give the answer as well. ( give the steps you did to

Sonbull [250]

Huh? what’s the question for #3?

7 0

3 years ago

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