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LUCKY_DIMON [66]

2 years ago

14

30% of consumers prefer to purchase elecktronicks online you randomly select 8 consumers find the probability that the number of

consumers who prefer to purchase electronics online is a exactly 5 be more than 5 &c at most 5

1 answer:

Lapatulllka [165]2 years ago

5 0

Answer:

see below

Step-by-step explanation:

Take the number of people surveyed and multiply by 30 %

8 * 30%

Change to decimal form

8 * .3

2.4

About 2.4 will purchase online

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Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

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2 years ago

If 8 = 54 and v = 17, Find m.

zhenek [66]

Answer:

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Step-by-step explanation:

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2 years ago

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grandymaker [24]

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2 years ago

Read 2 more answers

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago

Which choice most effectively sets up the

tatiyna

Option D. However, despite its many utilitarian benefits, colleges have not always supported the study of philosophy.

Which choice most effectively sets up the information that follows?

Despite philosophy teaching useful tools for academic and professional achievement, only 18 percent of the American colleges incorporated the course within curriculum, thus indicating their lack of support.
Hence, Option D is correct. The other options do not express this condition.

To know more about reading comprehension, refer:

brainly.com/question/23343740

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6 0

1 year ago