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3 years ago

I need help with the equation!

Mathematics

2 answers:

natka813 [3]3 years ago

8 0

I think it’s y=w-10, since I see a pattern of subtraction

fenix001 [56]3 years ago

8 0

Yo faith!

Question 3: Use the equation y= mx + b where m equals slope or the rate of change and b equals the y-intercept.

We already have b, which is 100. The reason why it's 100 is because the y-intercept is where the line crosses directly over the y-intercept. To do so, the x-value must be 0.

Thus y = mx + 100

The slope/ROC can easily be said to be -10 as the x value changes by adding 1 and the y value changes by subtracting 10. However, let's just presume that we didn't know this and couldn't use mental math.
To calculate the slope, we'll use the formula $\frac{y^2 - y^1}{x^2 - x^1}$ Take two points and insert them. I've chosen them for you:
1. (1,90)
2. (2,80)
$\frac{80 - 90}{2-1}$ ⇒ $\frac{-10}{1}$ ⇒ -10

Therefore your equation, Faith, is y = -10x + 100

Question 1 of C:
Graph - If the ordered-pair points formulate a straight line.
Table - Constant rate of change/slope for the x and y values.
Equation - No exponents are present.

Question 2 of C: Not sure what ''previous problems'' are given that they are not supplied.

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Task: Volume & Surface Area

Triss [41]

Okay so starting off I get that this math can be really confusing but you’ll get it if you keep working at it. Don’t give up you got this. For part it it is asking for the volume in cubic feet to do this you multiple H•W•L

H=hight

W=Width

L=Length

Now you don’t really need to know exactly which side is the H,L, or W but since you only have 3 sides with domentions you know that you multiply all three sides now it doesn’t matter what order you do it in.

Please respond if this helped for part A. You got this keep your head up.

3 0

3 years ago

Given the figure below, find the values of x and z.

N76 [4]

Answer:

x=9

z=73

Step-by-step explanation:

Angle 107 and 8x+35 are vertical angles, so they are equal

107 = 8x+35

Subtract 35 from each side

107-35 = 8x+35

72 = 8x

Divide by 8

72/8 = 8x/8

9 =x

We also know that 107 and z are supplementary angles since they form a straight line. This means they add to 180 degrees

107+z = 180

Subtract 107 from each side

107-107+z=180-107

z =73

5 0

3 years ago

At the movie theatre, child admission is $5.20 and adult admission is $9.70. On Sunday three time as many adult tickets as child

JulsSmile [24]

Answer:

23 child tickets were sold

Step-by-step explanation:

Using the information given, we can set up an equation to solve for the number of child tickets sold. Since there were three times as many adult tickets as child tickets sold, we can assign the variable 'x' to represent the number of child tickets and '3x' to represent the number of adult tickets. Since we know the cost of each ticket, as well as the total sales, we can set up the following equation:

5.20x + 9.70(3x) = 788.90

Simplify 5.20x + 29.1x = 788.90

Combine like terms: 34.3x = 788.90

Divide both sides by 34.3: x = 23 child tickets

3 0

3 years ago

Adam had silly putty 4 5/6 inches long. If he stretched it 2 2/3 times it's current length how long would it be?

Nikitich [7]

You multiply the 2 together 4 5/6 and 2 2/3.
4 5/6=29/6
2 2/3=8/3
you multiply the tops together then the bottoms together
29*8=232
3*6=18
232/18=116/9

8 0

3 years ago

Read 2 more answers

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago