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Nezavi [6.7K]
3 years ago
10

Need help ASAP please

Mathematics
1 answer:
Sveta_85 [38]3 years ago
5 0

Answer:

bruh ur so dumb

Step-by-step explanation:

google it

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Carlos found the area of the figure. Check his work, and explain any errors. 4 cm TheRectangle:(2)(1.5) = 3 cm 2 cm Triangle:(1)
lesya [120]

Answer:

Your answer is 5.5 cm².

If this helps you, mark me brainliest!!

6 0
2 years ago
I need help with how to reason it
artcher [175]

Answer:

X=80

Step-by-step explanation:

As 100⁰ is Opposite to B and AD and EH Are PARALLEL so B=100⁰

180-100

=80⁰

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4 0
2 years ago
The math equation: p(x)=x^2-10x+16 what is the answer?​
Gemiola [76]

(x+2)(x+8)

so x=-8 or x=-2

6 0
3 years ago
Solve the inequality |6x + 2| &lt; 10 and graph its solution.
mars1129 [50]
This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

  (6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12        Divide both sides by 6.
     x > -12/6
     x > -2.

Combined solution:   x < 4/3  and x > -2

  -2 < x < 4/3.

Graph is a line on the number line between -2 and 4/3.  
 
-2 and 4/3 are excluded from solution.
8 0
3 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
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