Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and 
Therefore segment NO is parallel to the segment KL.
Answer:
64 is the perfect square
Step-by-step explanation:
its the perfect square because the square root is 8 and 8 is a whole number therefore 64 is the perfect square here.
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Answer:
8/15
Step-by-step explanation:
Answer:
Step-by-step explanation:
square-based pyramid:
volume V = (⅓)b²h
= (⅓)7²·16
≅ 261.3 ft³
:::::
Can't help with question 3. I haven't learned triangle-based pyramids.
:::::
cone:
volume V = ⅓πr²h
= ⅓π17²·20
= 6052.8 yd³
:::::
can't help with question 7. Never did this kind of pyramid.
40%=0.4
0.4+1=1.4
4.5(1.4)=6.3
The answer is $6.30
