One number is eight less than a second number. Twice the first is 12 more than 4 times the second. Find the numbers.
1 answer:
Answer:
Step-by-step explanation:
"One number is eight less than a second number."
x = y-8
"Twice the first is 12 more than 4 times the second."
2x = 4y+12
substitution
2(y-8) = 4y + 12
2y - 16 = 4y + 12
2y = -28
y = -14
x = y-8 = -22
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