Question

One number is eight less than a second number. Twice the first is 12 more than 4 times the second. Find the numbers.

Answer 1

Answer:

Step-by-step explanation:

"One number is eight less than a second number."

x = y-8

"Twice the first is 12 more than 4 times the second."

2x = 4y+12

substitution

2(y-8) = 4y + 12

2y - 16 = 4y + 12

2y = -28

y = -14

x = y-8 = -22