Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.
Let's let the weight of a large box be L, and the weight of a small box be S.
We know that 5 large boxes and 3 small boxes is 120kg, so:
5L + 3S = 120
We also know that 7 large boxes and 9 small boxes is 234kg, so:
7L + 9S = 234
You can multiply the first equation by 3 to get:
15L + 9S = 360
See how now both equations have 9S? We can now subtract one from the other:
(15L+9S) - (7L+9S) = 360-234
8L = 126
L = 15.75
Now sub this value back into an equation:
(5x15.75) + 3S = 120
3S = 41.25
S = 13.75
Double check these values
(7x15.75) + (9x13.75)
= 110.25 + 123.75
=234, which is consistent with above.
So a large box is 15.75kg, and a small box is 13.75kg.
Hope this helped
The new equation is
<em>Y = (x-8)² </em>.
The other way to write it is like this: (you might not recognize it in this form)
Y = x² - 16x + 64
Answer:
Step-by-step explanation:
1. add the side lengths
The missing figure is attached
The value of a is 
⇒ 2nd answer
Step-by-step explanation:
Let as revise the Pythagoras Theorem
In the right triangle ABC, where ∠B is a right angle (AC is the hypotenuse, Ab and BC are the legs of the right angle)
- (AC)² = (AB)² + (BC)²
- (AB)² = (AC)² - (BC)²
- (BC)² = (AC)² - (AB)²
If BD is drawn perpendicular to AC, we can use these rules
- (AB)² = AD × AC
- (BC)² = CD × AC
- (BD)² = AD × CD
- AB × BC = BD × AC
In Δ WYZ
∵ m∠WYZ = 90°
- By using Pythagoras Theorem
∴ (WZ)² = (WY)² + (YZ)²
∵ WY = 4 units
∵ YZ = 3 units
∵ WZ = c units
∴ c² = (4)² + (3)²
∴ c² = 16 + 9 = 25
- Take √ for both sides
∴ c = 5
In Δ XWZ
∵ m∠XWZ = 90°
∵ WY ⊥ XZ
- We can use the rule (WZ)² = ZY × ZX
∵ (WZ)² = ZY × ZX
∵ WZ = 5 units
∵ ZY = 3 units
∵ ZX = (3 + a) units
∴ (5)² = 3(3 + a)
∴ 25 = 9 + 3a
- Subtract 9 from both sides
∴ 16 = 3a
- Divide both sides by 3
∴ a =
The value of a is
Learn more:
You can learn more about the rules of the right triangle in brainly.com/question/14390928
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