Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
There are 5 dimes and 13 nickels
Answer:
B
Step-by-step explanation:
To solve for x, we have to get x by itself. To do this, perform the opposite of what is being done to the equation.
5x+14=k
First, subtract 14 from both sides, because 14 is being added on to 5x. Subtraction is the opposite of addition.
5x+14-14=k-14
5x=k-14
Now, divide both sides by 5, because 5 and x are being multiplied. Division is the opposite of multiplication.
5x/5=k-14/5
x=k-14/5
So, the correct answer is choice B
2x-6=52 x= alternative schools
2x=58
x=29
There are 29 alternative schools in the county.
Answer:
thanks for the points then 23
Step-by-step explanation: