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The measure of an angle is 108°. What is the measure of a supplementary angle?

gogolik [260]

Answer:

72 degrees

Step-by-step explanation:

180-108=72

where I got 180: a supplementary angle is 180 degrees

8 0

3 years ago

A laptop producing company also produces laptop batteries, and claims that the batteries

gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

$H_0: \mu=4\\\\H_a:\mu< 4$

Step-by-step explanation:

The question is incomplete: To test this claim a sample or population standard deviation is needed.

We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.

NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

$H_0: \mu=4\\\\H_a:\mu< 4$

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902$

The degrees of freedom for this sample size are:

$df=n-1=500-1=499$

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

5 0

2 years ago

With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t

Klio2033 [76]

Answer:

Part a) $a=4g+10$ (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

The complete question is

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

$a=mg+b$

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

$m=\$4\ per\ game$

$b=\$10$

substitute

$a=4g+10$

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> $a=4(0)+10=\$10$

For g=1 ----> $a=4(1)+10=\$14$

For g=2 ----> $a=4(2)+10=\$18$

For g=3 ----> $a=4(3)+10=\$22$

For g=4 ----> $a=4(4)+10=\$26$

The table is

$\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]$

Part c) Use the values from your table to draw a graph

we have the ordered pairs

$(0,10),(1,14),(2,18),(3,22),(4,26)$

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

6 0

2 years ago

Pls help!!! Question in the picture

Wewaii [24]

Answer:

-7, - $\pi$ - $\sqrt{3}$ , 9

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

H₀: The variance of speeds does not exceeds 75 (mph)², i.e. σ² ≤ 75.

Hₐ: The variance of speeds exceeds 75 (mph)², i.e. σ² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, α = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0

3 years ago