2n - 7 × 1 = 15 × 3
2n - 7 = 45
2n = 45 + 7
2n = 52
n = 26
Have a nice days.........
What is the circumference of 13mm
2 answers:
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2n - 7 × 1 = 15 × 3
2n - 7 = 45
2n = 45 + 7
2n = 52
n = 26
Have a nice days.........
So hmm notice the picture below
thus, the perimeter of the gutter is just w + w + l, or 2w +l
thus
take the derivative of A(w), zero it out, check any critical points in the interval of (0, 22), for a maxima
recall, the aluminum sheet is just 22inches long, thus, whatever the "depth" or "w" is, has to be more than 0, and less than 22
thus, the perimeter of the gutter is just w + w + l, or 2w +l
thus
take the derivative of A(w), zero it out, check any critical points in the interval of (0, 22), for a maxima
recall, the aluminum sheet is just 22inches long, thus, whatever the "depth" or "w" is, has to be more than 0, and less than 22
Answers:
1) Graph Line 1
a) Graph: Please, see the attached graph.
b) (Line 1) Main Street (Equation in slope intercept form): y=(1/3)x+4
2) Graph Line 2
a) Graph: Please, see the attached graph.
b) Y intercept: (0,10)
c) X intercept: (5,0)
d) (Line 2) Street Equation in Standard Form: y+2x=10
3) Grap Line 3
a) Graph: Please, see the attached graph.
b) (Line 3) Street Equation in Point Slope Form: <u>y-3=(5/3)(x+3)</u>
Street Equation in Slope Intercept Form: <u>y=(5/3)x+8</u>
Solution:
1) Graph Line 1: (Main Street)
a) Graph the line formed from the two given points (9,7) (-9,1)
Please, see the attached graph.
b) Find the street equation in slope intercept form
P1=(9,7)=(x1,y1)→x1=9, y1=7
P2=(-9,1)=(x2,y2)→x2=-9,y2=1
m=(y2-y1)/(x2-x1)
m=(1-7)/(-9-9)
m=(-6)/(-18)
m=6/18
m=(6/6)/(18/6)
m=1/3
Point Slope form:
y-y1=m(x-x1)
y-7=(1/3)(x-9)
Slope Intercept Form:
y-7=(1/3)x-(1/3)(9)
y-7=(1/3)x-(1)(9)/3
y-7=(1/3)x-9/3
y-7=(1/3)x-3
y-7+7=(1/3)x-3+7
y=(1/3)x+4
2) Graph Line 2
a) Graph the line given the x and y intercepts
y intercept: 10
x intercept: 5
Please, see the attached graph
b) Y intercept
y intercept: b=10
Y intercept: (0,b)→Y intercept: (0,10)
c) X intercept
x intercept: a=5
X intercept: (a,0)→X intercept: (5,0)
d) Find the Street Equation in Standard Form
P1=(0,10)=(x1,y1)→x1=0, y1=10
P2=(5,0)=(x2,y2)→x2=5, y2=0
m=(y2-y1)/(x2-x1)
m=(0-10)/(5-0)
m=(-10)/(5)
m=-2
Point Slope Form:
y-y1=m(x-x1)
y-10=(-2)(x-0)
y-10=(-2)(x)
y-10=-2x
Standard Form:
y-10+10+2x=-2x+10+2x
y+2x=10
3) Graph Line 3
a) Graph the line given a point and the slope. (-3,3); m=5/3
Point 1: P1=(-3,3)=(x1,y1)→x1=-3, y1=3
Slope: m=5/3
m=dy/dx
5/3=dy/dx→dy=5, dx=3
Point 2: P2=(x2,y2)
x2=x1+dx→x2=-3+3→x2=0
y2=y1+dy→y2=3+5→y2=8
Point 2: P2=(x2,y2)→P2=(0,8)
Please, see the attached graph.
b) Find the Street Equation in Point Slope Form
Point Slope Form:
y-y1=m(x-x1)
y-3=(5/3)(x-(-3))
y-3=(5/3)(x+3)
Slope Intercept Form:
y-3=(5/3)x+(5/3)(3)
y-3=(5/3)x+(5)(3)/3
y-3=(5/3)x+15/3
y-3=(5/3)x+5
y-3+3=(5/3)x+5+3
y=(5/3)x+8
