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likoan [24]
2 years ago
12

What is the length of CO?

Mathematics
1 answer:
posledela2 years ago
8 0

Answer:

Pythagorean theorem, eh?

Step-by-step explanation:

The way to do this is use the radius-tangent angle theorem thing...

It states that, a radius that intersects a point of tangency(I think that's what it's called) is perpendicular to the tangent. Thus, CW is perpendicular to OW!

Thus, it forms a right triangle, where we can use Pythagorean Theorem!

If you don't know what it is, check the internet! It's pretty simple.

CW^2+OW^2=OC^2\\144+81=OC^2\\225=OC^2\\OC=15

So, there you go! Hope this helps!

NOTE: This answer was recently deleted for violating community guidelines, so I just re-uploaded it!(and edited it) So if you do need more help, do some research!

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What is the image of (1, -6) for a 270° counterclockwise rotation about the origin?
MArishka [77]

Answer:

6,1

Step-by-step explanation:

6 0
3 years ago
The perimeter of a rectangular field is 320320 yd. the length is 2020 yd longer than the width. find the dimensions.
hichkok12 [17]
The sum of length and width is half the perimeter, 160 yd. The length is the average of the sum and difference of dimensions:
.. (160 +20)/2 = 90
Then the width is 160 -90 = 70

The rectangular field is 70 yd by 90 yd.
6 0
3 years ago
Frankie wants to build a path from one corner of his hard to the opposite corner his yard measures 20ft x 32ft what will be the
Papessa [141]

Answer:

37.7 feet

Step-by-step explanation:

Given that:

Measurements of Frankie's yard = 20ft x 32ft

He wants to build a path from one corner to another.

To find:

The length of path = ?

Solution:

Let us consider a rectangle ABCD as shown in the attached image in the answer area.

We are given the two adjacent sides of a rectangle and we have to find diagonal of the rectangle.

To find the diagonal, we can use the Pythagorean Theorem.

We are given the base and perpendicular of the right angled triangle and we have to find the hypotenuse.

According to Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Diagonal = 20^2 + 32^2\\\Rightarrow Diagonal = 400 + 1024\\\Rightarrow Diagonal = \bold{37.7\ ft}

4 0
3 years ago
What is the end behavior? 10 points!!
Colt1911 [192]

Given:

The given function is:

f_1(x)=-3\cdot 2^{x-5}-4

The graph of the function is given.

To find:

The end behavior of the given function.

Solution:

We have,

f_1(x)=-3\cdot 2^{x-5}-4

From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

Therefore, the end behaviors of the given function are:

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

4 0
3 years ago
If AD=6 and AB=24, find AC
ruslelena [56]
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12
6 0
3 years ago
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