The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
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The answer is 500 becuase it is
Answer:
(y - 2)(y - 6)
Step-by-step explanation:
To factorise
Consider the factors of the constant term (+ 12) which sum to give the coefficient of the y- term (- 8)
The factors are - 2 and - 6
since - 2 × - 6 = + 12 and - 2 - 6 = - 8, hence
y² - 8y + 12 = (y - 2)(y - 6)