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astraxan [27]
3 years ago
13

A triangular tent door has an area of 15 square feet. The height is five feet. What is the base?

Mathematics
2 answers:
Serggg [28]3 years ago
7 0

Answer:

Base = 6 feet

Step-by-step explanation:

Area of Triangle = \frac{1}{2} Base*Height

<u><em>For finding Base:</em></u>

Base = \frac{2(Area)}{Height}

Where Area = 15, Height = 5

Base = \frac{2(15)}{5}

Base = 2*3

Base = 6 feet

Pavel [41]3 years ago
7 0

Answer:

The base is 6 feet long.,

Step-by-step explanation:

Area of a triangle = 1/2 * base * height so we have

1/2 b h = 15

1/2 b * 5 = 15

2.5 b = 14

b = 15/2.5

b = 6 feet.

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nataly862011 [7]

Answer:

: Use the Pythagorean Theorem

{c}^{2}  =  {a}^{2}  +  {b}^{2}

{c}^{2}  =  {5}^{2}  +  {12}^{2}

{c}^{2}  = 25 + 144

{c}^{2}  = 169

c =  + 13

6 0
3 years ago
1.4z + -0.6= .2 (5 +3z)
Gennadij [26K]
Z=2/3
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3 0
4 years ago
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If the end behavior is increasing on the left and decreasing on the right, which statement must be true about the function?
tatiyna

Answer:

The degree is even and the leading coefficient is negative.

Step-by-step explanation:

Given that the end behavior of the function is decreasing on the right, this means that x approaches positive infinity as y approaches negative infinity, which tells us that our leading coefficient is negative. Additionally, since our function is increasing on the left, then our function is even, which is symmetric to the origin.

8 0
2 years ago
8. A model airplane is shot into the air. Its path is approximated by the
rjkz [21]

Here is another one of those " quadratic word problems " at hand, which is great!

By the function that is given to us ( which I believe is meant to be h(t) = - 5t^2 + 251 ) the airplane is launched at a height of 251 metres, with no velocity. Anyhow, we need to determine the duration with which the airplane will strike the ground, and to do so we can set up the following equation, - 5t^2 + 251 = 0 - solving for t, otherwise known to be the time!

See the procedure below -

-5t^2+251=0 - Subtract 251 from either side,

-5t^2=-251 - Divide either side by - 5,

t^2=\frac{251}{5} - And, now isolate t, receiving two solutions,

t=\sqrt{\frac{251}{5}},\:t=-\sqrt{\frac{251}{5}}

However, time can't be a negative value. Thus our solution is \sqrt{251 / 5}, which is ( about ) 7.085 seconds!

3 0
3 years ago
Evaluate:<br> g(x) = 3•2^x+2 + 3<br> g(3)
sertanlavr [38]

If the 3 is supposed to be replaced by any x's, then the answer would be 29 I believe.

4 0
3 years ago
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