1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
seropon [69]
3 years ago
12

What can be used to show the difference in variation for two populations that have equivalent measures of center?.

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0
There’s no answer for that it just depends
You might be interested in
Please help asap (:
Korolek [52]
For this case we first define the variable:
 x = number of terms.
 The equation that models the problem is:
 f (x) = 3.4 - 0.6x
 We have then that the first four terms are:
 x = 1
 f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
 x = 2
 f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
 x = 3
 f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
 x = 4
 f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
 Answer:
 
The rule for the sequence is:
 
f (x) = 3.4 - 0.6x
 option 1
7 0
3 years ago
Read 2 more answers
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
S_A_V [24]
The answer is C :)


C
6 0
3 years ago
Help please I will be marking brainliest!!!
viktelen [127]

Answer:

Step-by-step explanation:

d

6 0
3 years ago
For the following pairs of equations explain why the equations are NOT equivalent.
Serga [27]
If you were to make both x's equivalent, you'd have to multiply the first equation by 2 to get rid of the coefficient, 1/2. However, you'd have to multiply 2 onto -8 as well, therefore the equation would turn into x - 16 = 18. That is not equivalent to x - 8 = 18.
7 0
3 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
Other questions:
  • The distance d (in miles) you travel in a car is given by the two equations shown, where t is the time (in hours) and g is the n
    7·2 answers
  • Give a solution I needed it urgent
    7·2 answers
  • -3x(x + y) +5y<br> if x=2 <br> y= -5
    6·2 answers
  • Find the equation of the line passing through the given points, (1,5) and (2, 7). Which
    12·1 answer
  • HellPlease help I have no idea what the answer is
    8·2 answers
  • Select the correct difference.<br> -3z^7- (-5z^7)
    15·2 answers
  • 5 &lt; x + 10 <br> what does x equal??
    14·2 answers
  • Each of the following sets of numbers represents dollars. Which set of numbers is most appropriate to label the six tick marks a
    5·1 answer
  • Which of the following are possible side lengths for a triangle
    13·1 answer
  • If m &lt; 8 = 106 and m &lt; 3 = (6x-4) what is the value of x.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!