Question

Find the sum of the terms.

Answer 1

Answer:

C

Step-by-step explanation:

Given

$\frac{x}{x^2+3x+2}$ + $\frac{3}{x+1}$ ← factor the denominator of first fraction

= $\frac{x}{(x+1)(x+2)}$ + $\frac{3}{x+1}$

Multiply the numerator/ denominator of second fraction by (x + 2)

= $\frac{x}{(x+1)(x+2)}$ + $\frac{3(x+2)}{(x+1)(x+2)}$

The denominators are now common, so add the numerators leaving the denominator, that is

= $\frac{x+3x+6}{(x+1)(x+2)}$

= $\frac{4x+6}{(x+1)(x+2)}$ → with numerator 4x + 6 → C