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sineoko [7]
3 years ago
5

the length of a rectangular picture frame is twice the width the frame has a permit from her murder of 96 in write and solve a s

ystem of equations to represent the solution let X represent the width of the frame and it lives represent the length of the frame interpret the solution​
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

16 is the width 32 is the length

Step-by-step explanation:

L = 2x

96 = 2L + 2x           Substitute the first equation into the second equation for L

96 = 2(2x) + 2x       Multiply

96 = 4x + 2x           Add

96 = 6x                   Divide both sides by 6

16 = x

Plug this into the first equation to solve for the length

L = 2(16)                  Multiply

L = 32

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Dons plumbing charges $15 per hour plus a service fee of $40 for coming out to your house. Write the equation modeling this situ
sladkih [1.3K]

Answer:

15x+40

Step-by-step explanation:

x would be the number of hours he is at the home

5 0
4 years ago
1. The figure shows the regular triangular pyramid SABC. The base of the pyramid has an edge AB = 6 cm and the side wall has an
Musya8 [376]

Given:

• AB = 6 cm

,

• SM = √15 cm

Let's solve for the following:

• 1) the base elevation AM.

Given that we have a regular triangular pyramid, the length of the three bases are equal.

AB = BC = AC

BM = BC/2 = 6/2 = 3 cm

To solve for AM, which is the height of the base, apply Pythagorean Theorem:

\begin{gathered} AM=\sqrt{AB^2-BM^2} \\  \\ AM=\sqrt{6^2-3^2} \\  \\ AM=\sqrt{36-9} \\  \\ AM=\sqrt{27} \\  \\ AM=5.2\text{ cm} \end{gathered}

The base elevation of the pyramid is 5.2 cm.

• (2)., The elevation SO.

To find the elevation of the pyramid, apply Pythagorean Theorem:

SO=\sqrt{SM^2-MO^2}

Where:

SM = √15 cm

MO = AM/2 = 5.2/2 = 2.6 cm

Thus, we have:

\begin{gathered} SO=\sqrt{(\sqrt{15})^2-2.6^2} \\  \\ SO=\sqrt{15-6.76} \\  \\ SO=2.9\text{ cm} \end{gathered}

Length of SO = 2.9 cm

• (3). Area of the base:

To find the area of the triangular base, apply the formula:

A=\frac{1}{2}*BC*AM

Thus, we have:

\begin{gathered} A=\frac{1}{2}*6^*5.2 \\  \\ A=15.6\text{ cm}^2 \end{gathered}

The area of the base is 15.6 square cm.

• (4). Area of the side surface.

Apply the formula:

SA=\frac{1}{2}*p*h

Where:

p is the perimeter

h is the slant height, SM = √15 cm

Thus, we have:

\begin{gathered} A=\frac{1}{2}*(6*3)*\sqrt{15} \\  \\ A=34.86\text{ cm}^2 \end{gathered}

• (5). Total surface area:

To find the total surface area, apply the formula:

TSA=base\text{ area + area of side surface}

Where:

Area of base = 15.6 cm²

Area of side surface = 34.86 cm²

TSA = 15.6 + 34.86 = 50.46 cm²

The total surface area is 50.46 cm²

• (6). Volume:

To find the volume, apply the formula:

V=\frac{1}{3}*area\text{ of base *height}

Where:

Area of base = 15.6 cm²

Height, SO = 2.9 cm

Thus, we have:

\begin{gathered} V=\frac{1}{3}*15.6*2.9 \\  \\ V=15.08\text{ cm}^3 \end{gathered}

The volume is 15.08 cm³.

ANSWER:

• 1.) 5.2 cm

,

• 2.) 2.9 cm

,

• 3.) 15.6 cm²

,

• 4.) 34.86 cm²

,

• (5). 50.46 cm²

,

• 6). 15.08 cm³.

7 0
1 year ago
Tell whether the statement is true or false.
kherson [118]
False I think

More than three lines of symmetry
5 0
4 years ago
Read 2 more answers
Helene drove 70 km on 4 L of gasoline. Which proportion would help determine how far she can travel on a full 30 L tank of gasol
kondor19780726 [428]
I think it would be 70/4=x/30 because if she went 70km on 4L she could go Xkm on 30L
3 0
4 years ago
Find the H.C.F of 144,180,240,300​
aliina [53]
Answer:
GCF = 12

for the values 144, 180, 240, 300

Solution by Factorization:

The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, 144

The factors of 180 are: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

The factors of 300 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 25, 30, 50, 60, 75, 100, 150, 300

Then the greatest common factor is 12.
8 0
3 years ago
Read 2 more answers
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