Given:
• AB = 6 cm
,
• SM = √15 cm
Let's solve for the following:
• 1) the base elevation AM.
Given that we have a regular triangular pyramid, the length of the three bases are equal.
AB = BC = AC
BM = BC/2 = 6/2 = 3 cm
To solve for AM, which is the height of the base, apply Pythagorean Theorem:

The base elevation of the pyramid is 5.2 cm.
• (2)., The elevation SO.
To find the elevation of the pyramid, apply Pythagorean Theorem:

Where:
SM = √15 cm
MO = AM/2 = 5.2/2 = 2.6 cm
Thus, we have:

Length of SO = 2.9 cm
• (3). Area of the base:
To find the area of the triangular base, apply the formula:

Thus, we have:

The area of the base is 15.6 square cm.
• (4). Area of the side surface.
Apply the formula:

Where:
p is the perimeter
h is the slant height, SM = √15 cm
Thus, we have:

• (5). Total surface area:
To find the total surface area, apply the formula:

Where:
Area of base = 15.6 cm²
Area of side surface = 34.86 cm²
TSA = 15.6 + 34.86 = 50.46 cm²
The total surface area is 50.46 cm²
• (6). Volume:
To find the volume, apply the formula:

Where:
Area of base = 15.6 cm²
Height, SO = 2.9 cm
Thus, we have:

The volume is 15.08 cm³.
ANSWER:
• 1.) 5.2 cm
,
• 2.) 2.9 cm
,
• 3.) 15.6 cm²
,
• 4.) 34.86 cm²
,
• (5). 50.46 cm²
,
• 6). 15.08 cm³.
Answer:
GCF = 12
for the values 144, 180, 240, 300
Solution by Factorization:
The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, 144
The factors of 180 are: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180
The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240
The factors of 300 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 25, 30, 50, 60, 75, 100, 150, 300
Then the greatest common factor is 12.