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olga nikolaevna [1]
3 years ago
9

If 50 apples cost $25, then 75 apples would cost how much?

Mathematics
2 answers:
NikAS [45]3 years ago
4 0

Answer:

$37.5

Step-by-step explanation:

we can look at this problem using rates:

50=$25

25=$12.5

so we can add $12.5 to $25 because 50+25=75 so our answer, 12.5+25=37.5

$37.5

kvasek [131]3 years ago
3 0

Answer:

Step-by-step explanation:

Cost of 1apple = 25/50

Cost of 75 apples

=\frac{25}{50}*75\\\\=\frac{1}{2}*75\\

= $ 37.50

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Answer:

155 Units

Step-by-step explanation:

Rate of Bug (given) = 11 units PER MINUTE

It never changed direction, so it was going in positive direction (assume).

In 7:15 pm (evening), it was at Point 100,

We want the point at which it was at 7:20 pm.

7:20pm - 7:15pm = 5 minutes

So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:

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Assuming he is going in positive direction, the bug will be at:

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What is the value of x in the equation:<br><br> -10x -19 = 19 -8x
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Answer:

x = -19

Step-by-step explanation:

-10x - 19 = 19 - 8x

-10x + 8x = 19 + 19

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x = -19

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How to find r in this equation using combination formula C(8,r)=28<br>​
slavikrds [6]

Answer:

r = 2

Step-by-step explanation:

We have the formula of ^nC_r = \frac{n!}{r! (n-r)!}

Now, it is given that ^8C_r = \frac{8!}{r! (8-r)!} = 28 ........ (1)

And we have to find the value of r which satisfy the above equation.

So, r! (8-r)! = \frac{8!}{28} = \frac{40320}{28} = 1440

Now, we have to use the trial method to find the value of r.

For r = 1, 1! (8-1)! = 7! = 5040 \neq 1440

Hence, r can not be 1.

Now, put r = 2, 2! (8-2)! = 2 \times 6! = 1440

Therefore, r = 2 (Answer)

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Answer:

no solution ever

Step-by-step explanation:

https://simplisico.com/share/q/B8ZG0KyiS5OVu7vDDhWMr37x

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3 years ago
Is the graph increasing, decreasing, or constant?
djyliett [7]

Answer:

It is increasing.

Step-by-step explanation:

Given the graph of a straight line, there are several ways to find its equation.

Method 1: This method works only if the y intercept is visible.

Find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Get b from inspection of the y intercept of the graph.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 2: This method works even if the y intercept is not visible.

As in method 1, find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Substitute the number that you obtained for m into the equation y = m x + b. Also, take one of the points, say (x1, y1), and substitute its coordinates into the equation. This gives:

y1 = m x1 + b

It may not look like it, but this equation has only one variable, b, and you can easily solve for it.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 3: This method has the advantage that it uses only algebra, not geometry, and can be applied to any type of function, not just the straight line:

Find two points, (x1, y1) and (x2, y2), that are on the line. Take the first point, (x1, y1), and substitute it into the straight line equation, y = m x + b. This gives:

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Similarly, take the second point, (x2, y2), and substitute it into the straight line equation, y = m x + b. This gives:

y2 = m x2 + b

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Find b by back-substitution. To be specific, substitute the number that you obtained for m into one equation of the system of equations, say into y1 = m x1 + b. It may not look like it, but this equation has only one variable, b, and you can easily solve for it

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