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3 years ago

WILL CROWN BRAINLIEST, GIVE THANKS, AND AMAZING RATING

Mathematics

1 answer:

astra-53 [7]3 years ago

5 0

stretch the compass by a considerable amount (just not too short, or it's hard to draw) and put the point on W. Draw an arc, with the point still on W. Do the same to X (placing the compass point on X and and drawing an arc), but the length of how stretched the compass is must me the SAME. If you did it right, you would have two arcs where a point meets between them. Using a ruler, draw a line from the dot down to the line WX. Then you should see the line's perpendicular bisector( perpendicular bisector is a line running down a certain line so the angles make a 90 degree )!

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Mary says the pen for her horse is an acute right triangle . is this possible ?

hjlf

Yes it is possible because the acute angle is less then 90 degrees meaning its inside the angle

7 0

3 years ago

Read 2 more answers

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

3 years ago

15 over 1000 wrote in scientific notation

Katena32 [7]

Answer:

1.5*10^-2

Step-by-step explanation:

You mean 15/1000 written in scientific notation?

In this case, it would be- 1.5*10^-2.

3 0

3 years ago

In a 5/6 pound mixture of sand and gravel, 1/4 pound is gravel.

USPshnik [31]

<span>Total mass of mixture is given as 5/6 pound, in which 1/4 pound is gravel. Amount of sand in the mixture will be 5/6 - 1/4 = 7/12 So, the ratio of sand to that of gravel in given mixture is 7/12:1/4 = 7:3. i.e every 10 parts of mixture contain 7 parts of sand and 3 parts of gravel. If we are given 1-pound of same mixture, it will contain 1 * 3/10 pound gravel, i.e. 0.3 pound.</span>

8 0

3 years ago

Read 2 more answers

Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde

zmey [24]

Answer:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

$p_v =P(t_{(19)}>1.638)=0.0589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=7.03$ represent the sample mean

$s=9.42$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =3.58$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :

Null hypothesis: $\mu \leq 3.58$

Alternative hypothesis: $\mu > 3.58$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since is a right tailed test the p value would be:

$p_v =P(t_{(19)}>1.638)=0.0589$

Conclusion

7 0

3 years ago