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Dmitriy789 [7]
3 years ago
11

WILL CROWN BRAINLIEST, GIVE THANKS, AND AMAZING RATING

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

stretch the compass by a considerable amount (just not too short, or it's hard to draw) and put the point on W. Draw an arc, with the point still on W. Do the same to X (placing the compass point on X and and drawing an arc), but the length of how stretched the compass is must me the SAME. If you did it right, you would have two arcs where a point meets between them. Using a ruler, draw a line from the dot down to the line WX. Then you should see the line's perpendicular bisector( perpendicular bisector is a line running down a certain line so the angles make a 90 degree )!

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For each statement below, determine if it is True or False. Justify your answer. (a) If a linear system has infinitely many solu
DiKsa [7]

Answer:

the answer a is false b is true

3 0
2 years ago
Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr
Minchanka [31]

Answer:

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  The margin of error is the range of values below and above the sample statistic in a confidence interval.  Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  [tex]p_1 represent the real population proportion for 1

\hat p_1 =0.768 represent the estimated proportion for 1

n_1=92 is the sample size required for 1

p_2 represent the real population proportion for 2

\hat p_2 =0.646 represent the estimated proportion for 2

n_2=95 is the sample size required for 2

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}  

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

ME= \frac{0.2753-(-0.0313)}{2}=0.1533

And we know that the margin of erro is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}

We have all the values except the value for z_{\alpha/2}

So we can find it like this:

0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}

And solving for z_{\alpha/2} we got:

z_{\alpha/2}=2.326

And we can find the value for \alpha/2 with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98 or 98%

7 0
3 years ago
Emails arrive at the server of a company at the rate of an average of 10 per hour. It is assumed that a Poisson process is a goo
fomenos

Answer:

0.37

Step-by-step explanation:

we have given that emails arrives at the server at the rate of 10 per hour means \frac{10}{60}=0.166  per minute

we have to find the probability that the time difference between the two email is more than 2 minute

so probability P\left ( X> 2 \right )=e^{-2\lambda }=e^{-2\times 0.166}=0.7166

4 0
3 years ago
If 1/2x = a= 2/3y and x + y= na, what is the value of n?
Fynjy0 [20]

Answer:

Step-by-step explanation:

\frac{1}{2} x=a=\frac{2}{3} y\\\frac{1}{2}x=a\\x=2a \\\frac{2}{3} y=a\\y=\frac{3}{2} a\\x+y=2a+\frac{3}{2} a=\frac{4a+3a}{2} =\frac{7}{2} a=na\\n=\frac{7}{2}

4 0
2 years ago
Find the volume.<br> 15 points
Anton [14]

Answer:

the volume is 196

Step-by-step explanation:

17x8=136

6x10=60

136+60=196

3 0
3 years ago
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