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3 years ago

WILL CROWN BRAINLIEST, GIVE THANKS, AND AMAZING RATING

Mathematics

1 answer:

astra-53 [7]3 years ago

5 0

stretch the compass by a considerable amount (just not too short, or it's hard to draw) and put the point on W. Draw an arc, with the point still on W. Do the same to X (placing the compass point on X and and drawing an arc), but the length of how stretched the compass is must me the SAME. If you did it right, you would have two arcs where a point meets between them. Using a ruler, draw a line from the dot down to the line WX. Then you should see the line's perpendicular bisector( perpendicular bisector is a line running down a certain line so the angles make a 90 degree )!

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Shjdksjcksmcjcsnuckamc

irina1246 [14]

Answer:

you should make the picture more clear, i cant see the answer choices

8 0

2 years ago

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Bob is thinking about leasing a car with a MSRP of $24,000 for three years. After three years, the leasing company expects the c

KengaRu [80]

Answer:C. 17,280

Step-by-step explanation:It this way because it cant be 3k obv or 6k. And it says 72% down not up so not d either :D

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3 years ago

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Jim went to the playground. He played on the swings for 45 minutes and went on the slide for 55 minutes. It was 4:35 P.M. when J

aleksklad [387]

Answer:

2:55 P.M.

Step-by-step explanation:

First, add the amount of time Jim played outside; 45+55=100

100 minutes is equal to 1 hour 40 minutes.

If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.

Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.

To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.

Hope this helped !!!

4 0

2 years ago

Find the inverse of the given function.

kodGreya [7K]

For this case we must find the inverse of the following function:

$f (x) = - \frac {1} {2} \sqrt {x + 3}$

We follow the steps below:

Replace f(x) with y:

$y = -\frac {1} {2} \sqrt {x + 3}$

We exchange the variables:

$x = - \frac {1} {2} \sqrt {y + 3}$

We solve for "y":

$- \frac {1} {2} \sqrt {y + 3} = x$

Multiply by -2 on both sides of the equation:

$\sqrt {y + 3} = - 2x$

We raise both sides of the equation to the square to eliminate the radical:

$(\sqrt {y + 3}) ^ 2 = (- 2x) ^ 2\\y + 3 = 4x ^ 2$

We subtract 3 from both sides of the equation:

$y = 4x ^ 2-3$

We change y by f ^ {- 1} (x):

$f ^ {- 1} (x) = 4x ^ 2-3$

Answer: $f ^ {- 1} (x) = 4x ^ 2-3$

7 0

3 years ago

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Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling

sergeinik [125]

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are $2^{30}$ lilypads on the 30th, and $2^{29}$ lilypads on the 29th. This can be deduced multiplying succesively by 2.

4 0

2 years ago