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Hitman42 [59]
3 years ago
9

Three research departments have 8,6,7 members, respectively. Each department is to select a delegate and an alternate to represe

nt the department at a conference. In how many ways can this be done
Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

70,560 ways

Step-by-step explanation:

This problem is an arrangement problem, as the order of the two people chose in each department matters.

So, for each department, we have an arrangement:

First department: arrange of 8 choose 2: A(8,2) = 8!/2! = 8*7 = 56

Second department: arrange of 6 choose 2: A(6,2) = 6!/2! = 6*5 = 30

Third department: arrange of 7 choose 2: A(7,2) = 7!/2! = 7*6 = 42

The total number of ways is the product of each number of arranges, so:

Number of ways = 56 * 30 * 42 = 70,560

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Answer:

The domain is  (-∞,0) ∪ (0,1) ∪ (1, +∞)

Step-by-step explanation:

In order to be able to compute f/g (x), we need that x is on the domain of f and in the domain of g.

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In order to be able to compute f(x), we need that the denominator is different from 0, hence x≠0.

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In order to be able to compute g(x). we need x-1 to be different from 0, thus x≠1.

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Step-by-step explanation:

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