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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
A $60.50
Step-by-step explanation:
165 divided 3 = $55.00 per class
55.00 X 10% = 5.50 per class
55.00 + 5.50 = 60.50
answer:
-1
work:
y = mx+ b
so we can tell that the Y intercept is 1, so we can plug that in. ( + b is the y-intercept)
y = mx + 1
plug in some values to find the slope.
(-1, 2)
2 = -m + 1
- 1 - 1
1 = -1m
/-1 /-1
-1 = m
the slope is -1.
i hope this helps! :D
234/355/470/476/765
470 Is the median
