Estimate the area of the parallelogram.

If the original price is ₱450 and the rate of discount is 12%. A.What is the amount of reduction? B.What is the sale price?

Rudik [331]

Original price marked on the item = €450

rate of discount = 12%

A.
Discount amount = €450 × 12/100 = €54

So amount of reduction is €54

B.
Sale.price = original price - discount

= €450 - €54

= €396

Sale price is €396.

3 0

4 years ago

David y Angie tienen dos cartulinas iguales. David corta la suya en 3 trozos iguales y Angie la corta en 7 trozos. Los dos usan

Bess [88]

Answer:

(i) David ha empleado $\frac{2}{3}$ de la cartulina.

(ii) Angie ha empleado $\frac{2}{7}$ de la cartulina.

(iii) David ha usado más cartulina.

Step-by-step explanation:

El problema indica que David y Angie emplean una cartulina del mismo tamaño cada uno. David corta la suya en 3 pedazos iguales, mientras que Angie obtiene 7 pedazos iguales. Finalmente, cada uno emplea dos de sus pedazos. A continuación, respondemos a las preguntas del enunciado:

(i) ¿Qué fracción de cartulina ha usado David?

La fracción de cartulina empleada por David es igual a los pedazos utilizados divididos por el total de pedazos. Esto es:

$x = \frac{2}{3}$

David ha empleado $\frac{2}{3}$ de la cartulina.

(ii) ¿Qué fracción de cartulina ha usado Angie?

Aplicando el mismo procedimiento del punto anterior, tenemos que:

$x = \frac{2}{7}$

Angie ha empleado $\frac{2}{7}$ de la cartulina.

(iii) ¿Quién ha usado más cartulina?

La persona que ha usado la mayor cantidad de cartulina es aquella que tiene el menor denominador. Por tanto, David ha usado más cartulina.

7 0

3 years ago

the alexander family and jenkins family each used their sprinklers last summer. the water output rate for the alexander familys

Mumz [18]

Answer:
Alexanders family sprinkler used for 35.25 hours
And the Jenkins family sprinkler was used for 29.75 hours.

Step-by-step explanation:

Lets start with 2 assumptions, what if we only used the Alexander's family sprinklers, We can define X as the variable
$20x=1450$
$x= 72.5$
If we just used the Alexanders it would of took 72 hours and 30 minutes.

Now lets look at the Jenkins family sprinkler, lets define it as Y.
$25y=1450$
$y = 58$
With only the Jenkins it would of took 58 hours.

Now, if they just of shared the work equally among the two sprinklers, the Alexanders family doing 725 L and the Jenkins with the other half.
It would of took the Alexanders
$20x= 725$
$x=36.25$

Jenkins
$25y=725$
$y=29$

Making it a combined time of 65.25 hours. 15 minutes long of our 65 hour time.

Now the Jenkins sprinkler generates 5 more L than Alexanders per hour. Which means it would only take the Jenkins family 1 hours to make 25 liters but Alexanders would take $\frac{5}{4}$ hours. We know that 1 hour contains 60 minutes, which means $\frac{1}{4}$ of a hour contains 15 minutes.

So it would take Alexanders family sprinkler 15 minutes more to produce the same amount per hour that the Jenkins does.

So from this we can conclude that if the Jenkins family sprinkler was used more we can cut the extra 15 minutes off, making the answer That the

Alexanders family sprinkler used for 35.25 hours
And the Jenkins family sprinkler was used for 29.75 hours.