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ycow [4]
4 years ago
6

The digits of a two-digit number differ by 3. If the digits are interchanged, and the resulting number is added to the original

number, we get 143. What can be the original number?
Mathematics
2 answers:
Zanzabum4 years ago
6 0

Answer:

The original number could be 85.

Step-by-step explanation:

Let the 2 digits be x and y.

Let the number be xy then, assuming that x is the larger digit:

x - y = 3.

x = y + 3

Also

10y + x + 10x + y = 143

Substituting for x:

10y + y + 3 + 10(y + 3) + y = 143

22y + 33 = 143

22y = 110

y = 5.

So x = y + 3 = 8.

marin [14]4 years ago
3 0

Answer:

  • Let the unit digit be x and tens digit be x + 3

  • Therefore, the original number = 10(x + 3) + x

  • On interchanging, the number formed = 10x + x + 3

<h3><u>❍ According to Question now,</u></h3>

➥ 10(x + 3) + x + 10x + x + 3 = 143

➥ 10x + 30 + 12x + 3 = 143

➥ 22x + 33 = 143

➥ 22x = 143 - 33

➥ 22x = 110

➥ x = 110/22

➥ x = 5

<h2>__________________...</h2>

<h3>Therefore,</h3>

The unit digit number = x = 5

The tens digit number = x + 3 = 5 + 3 = 8

<h2>__________________...</h2>

The original number = 10(x + 3) + x

The original number = 10(5 + 3) + 5

The original number = 50 + 30 + 5

The original number = 85

Hence<u>,the original number is 85.</u>

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Answer:

a) Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

b) z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271    

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1) Data given and notation  

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p_{M}=\frac{28}{238}=0.118 represent the proportion of men  that write with their left hand

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\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the rate of left-handedness among males is less than that among females , the system of hypothesis would be:  

Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{28+62}{238+497}=0.122

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271  

4) Statistical decision

We have a significance level provided \alpha=0.05, and now we can calculate the p value for this test.  

Since is a one left side test the p value would be:  

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.05, 0,1,0.15 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant loer than the proportion of female that write with their left hand .  

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