Simplify by distributing: 3(x + 4)

omeli [17]

<h3>Answer: Choice C</h3>

domain = (-infinity, infinity)
range = (-infinity, 0)
horizontal asymptote is y = 0

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Explanation:

Since no division by zero errors are possible, and other domain restricting events are possible, we can plug in any x value we want. This means the domain is the set of all real numbers. Representing this in interval notation would be (-infinity, infinity).

The range is the set of negative real numbers, which when written in interval notation would be (-infinity, 0). This is because y = 5^x has a range of positive real numbers, and it flips when we negate the 5^x term. The graph of y = -5^x extends forever downward, and the upper limit is y = 0.

It never reaches y = 0 itself, so this is the horizontal asymptote. Think of it like an electric fence you can get closer to but can't touch.

7 0

3 years ago

Solve and explain <br> 4 20 <br> ___ = _____<br> x - 5 x - 7

Degger [83]

X = 9/2

i hope i have helped you out. simple math for me. :)

8 0

3 years ago

Find the amount of the annuity due. Round to the nearest cent.

Ber [7]

FVAD=515[((1+0.18/12)^(12*2)-1)/(0.18/12)]*(1+0.18/12)
FVAD=14967.46

5 0

3 years ago

Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin

vesna_86 [32]

Answer:

Yes, he will have enough paint to cover the tank with one layer of paint.

Step-by-step explanation:

We are given that Tublu buys a cylindrical water tank of height 1.4 m and diameter 1.1 m to catch rainwater off his roof. He has a full 2 liters tin of paint in his store and decides to paint the tank (not the base).

He uses 250 ml to cover 1 $\text{m}^{2}$ .

From the question, it is clear the area of the tank which needs to be painted is the lateral surface area (because the base is not included).

The lateral surface area of the cylinder = $2\pi rh$

where, r = radius of the cylinder = $\frac{\text{Diameter}}{2}$ = $\frac{1.1 }{2}$ = 0.55 m

h = height of the cylinder = 1.4 m

$\pi$ = 3.142 (given)

So, the lateral surface area of a cylindrical water tank = $2 \times 3.142 \times 0.55 \times 1.4$

= 4.84 $\text{m}^{2}$ .

Now, it is given in the question that; Tublu uses 250 ml to cover 1 $\text{m}^{2}$ area, this means that;

To cover 4.84 $\text{m}^{2}$ area, he will use paint = $4.84 \times 250$ = 1210 ml

Since he has a full 2 liters tin of paint in his store which is equal to 2000 ml but he need only 1210 ml of paint.

This means that yes, he will have enough paint to cover the tank with one layer of paint.

8 0

3 years ago

Please help answer this question it would help if multiple people answered so I could confirm a correct answer thank you

evablogger [386]

Answer:

53.33

Step-by-step explanation:

finding area of ΔPAM

using similar triangles

$\frac{4}{x}= \frac{12}{4}$

16 = 12x; x = $\frac{4}{3}$

ΔPAM = 4/3 * 4 * 1/2 = 16/6 = 8/3

ΔPAL = 4 * 12 * 1/2 = 24

24 + 8/3 = 80/3 (using fraction form for now, will round later)

since there are two ΔPLM (ΔLMU has same area since they are congruent)

we can multiply 80/3 by 2

80/3 * 2 = 160/3 = 53.33

4 0

3 years ago