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3 years ago

The equation is z=8+6x-px and you're solving for x

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

5 0

Answer:

x= z-8/6-p

it says my answer is to short so i'm going to write a bunch or words

kolbaska11 [484]3 years ago

4 0

Answer:

p= 6x−z+8 /x

Step-by-step explanation:

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RSB [31]

Answer:

Step-by-step explanation:

1 since it's -1 inside it moves to the right

and it's positive 3 outside so it goes up 3

8 0

2 years ago

If K is the midpoint of HJ, HK = x+6, and HJ =4x-6, then KJ = ?

barxatty [35]

4x-6= x+6
4x= x + 12
5x= 12
X= 12/5
X= 2.5

6 0

2 years ago

Graph the following linear function.<br> f(x) = 1/6x+3

Black_prince [1.1K]

Y-axis is 3
x-axis is -18

4 0

2 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

sladkih [1.3K]

Answer:

10.17 seconds

Step-by-step explanation:

substitute y=0 into the equation

0=-16x²+153x+98

then use the quadratic formula

a = -16

b= 153

c = 98

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

x₁= 10.17

x₂= -0.60

5 0

2 years ago

Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

7 0

3 years ago

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