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masya89 [10]
3 years ago
12

Write a linear equation passing through points (-7, -4) and (-5, -6)

Mathematics
1 answer:
STatiana [176]3 years ago
6 0
The answer is y = -x + 11
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Step-by-step explanation:

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3(x + 5)2 + 6 vertex
Tanya [424]

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The equation does not match the form of any conic section.

Not a Conic Section

Step-by-step explanation:

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2 years ago
What is the best way to convert metric units (I'm really bad at this...)
Vladimir [108]
Necesitas reconocer los múltiplos u submúltiplos del sistema métrico decimal si son lineales por cada nivel que avanzas multiplicas o divides con el 10
siempre y cuando la unidad de medida es el metro ese queda al centro.
Km Hm Dam m dm cm mm yo los ubico en escalera el metro queda al centro y de cualquier lugar que te posicionas,buscas a donde quieres convertir y revisas si vas a la derecha multiplicas por 10 o si vas a la izquierda divides entre 10 siempre y cuando sea un lugar a donde te vas a mover si son dos lugares es con el 100 por que 10x10 es 100 y si son tres lugares es con el 1000 porque es 10x10x10.
ejemplo 2000m convertirlos a Hm= 20 Hm dividí 2000 entre 100 porque me moví 2 lugares a la izquierda  otro ejem. 100 Dam convertirlos a cm=100000 porque 100x 1000 por que avance 3 lugares a la derecha
4 0
3 years ago
I need help plzz its due TODAYYY
kobusy [5.1K]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

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tensor-on-tensor regression: riemannian optimization, over-parameterization, statistical-computational gap and their interplay
Contact [7]

The purpose of the tensor-on-tensor regression, which we examine, is to relate tensor responses to tensor covariates with a low Tucker rank parameter tensor/matrix without being aware of its intrinsic rank beforehand.

By examining the impact of rank over-parameterization, we suggest the Riemannian Gradient Descent (RGD) and Riemannian Gauss-Newton (RGN) methods to address the problem of unknown rank. By demonstrating that RGD and RGN, respectively, converge linearly and quadratically to a statistically optimal estimate in both rank correctly-parameterized and over-parameterized scenarios, we offer the first convergence guarantee for the generic tensor-on-tensor regression. According to our theory, Riemannian optimization techniques automatically adjust to over-parameterization without requiring implementation changes.

Learn more about tensor-on-tensor here

brainly.com/question/16382372

#SPJ4

7 0
1 year ago
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