Kim performed a transformation on rectangle ABCD to create rectangle A'B'C'D', as shown in the figure below:

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

THE answer is A becuase if you rotate 270 it brings u to q1 and D is wrong bc 90 degrees counter clockwise, looking closly the shape on the figure on the right is A'B'C'D' the figure on the left is ABCD.

HOPES THIS HELPS

Sincerly BArry

Dmitry [639]3 years ago

7 0

Answer:

rotation of 90 degrees

Step-by-step explanation:

it is rotation of 90 degrees because if you put the rectangle on its side or turn 90 degrees either to the left or right it will be the same exact figure as the one on the right so you would do the opposite of that and take the shape on the right and put it standing straight up or turn it counterclockwise 90 degree

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A^2(64a^2-3)/3=27-4a^2/4

frutty [35]

The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
${a}^{2} (64 {a}^{2} - 3) = 64 {a}^{4} - 3 {a}^{2}$
Then set the denominators equal:
$\frac{ 256 {a}^{4} - 12 {a}^{2}}{12} = \frac{81 - 12 {a}^{2} }{12}$
Then remove the denominators and solve:
$256 {a}^{4} - 12 {a}^{2} = 81 - 12 {a}^{2}$
Eliminate -12a^2 by adding 12a^2 to both sides:
$256 {a}^{4} = 81$
Take the fourth root of them or take the square root twice:
$\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3$
Divide both sides by 4:
$a = \frac{3}{4} = 0.75$

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