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vodka [1.7K]
2 years ago
6

Robbie has 2 times as many apples as Bob. After receiving 35 more, Robbie now has 7 times as many as Bob. How many apples does B

ob have? ​
Mathematics
1 answer:
Hoochie [10]2 years ago
7 0

Answer:  18.5 apples

Step-by-step explanation:

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Marcus rented a movie for 4$ and some video games for $6 each he paid $22 how many games did he rent
galina1969 [7]

$22 - $4 (for the movie) = $18.

$18 / $6 (per game) = 3 games

8 0
3 years ago
Read 2 more answers
10. Shown is a circle centre o
Aleksandr [31]

Answer:

.

Step-by-step explanation:

6 0
3 years ago
(½) (6x + 3) = 7 – (3x + 1)
erastovalidia [21]

\tt Step-by-step~explanation:

To solve for x, we have to remember to isolate the variable.

\tt Step~1:

For 1/2, we can make that 0.5, since their values are equivalent. Our equation:

\tt (0.5)(6x+3)=7-(3x+1)

Let's distribute the 0.5 first.

\tt 0.5*6x=3x\\0.5*3=1.5

\tt Step~2:

Now, let's simplify the right side of the equation. We have to distribute the negative to 3x and 1.

\tt -1*3x=-3x\\-1*1=-1

Then, we simplify the entire expression.

\tt 7-3x-1=-3x+6

\tt Step~3:

Our equation now:

\tt 3x+1.5=-3x+6

Let's add 3x to the right and 3x to the left to simplify the -3x on the right side of the equation.

\tt 3x(+3x)+1.5=-3x (3x)+6\\6x+1.5=6

\tt Step~4:

Let's do the same thing we did in Step 3 to 1.5. Subtract 1.5 on both sides of the equation.

\tt 6x+1.5(-1.5)=6(-1.5)\\6x=4.5

\tt Step~5:

Finally, we divide both sides by 6 to isolate x.

\tt \frac{6x}{6} =x\\\frac{4.5}{6}= 0.75~or~\frac{3}{4}

\large\boxed{\tt Our~final~answer:~x=0.75~(or~\frac{3}{4})}

8 0
3 years ago
In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF  = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively

Read more about parallelograms at:

brainly.com/question/3050890

#SPJ1

8 0
1 year ago
I need help on a math problem<br> 48w^3+128w^2+4w-1<br> divided by<br> 4w
raketka [301]
Divide 4w to every term separately.

\sf\dfrac{48w^3+128w^2+4w-1}{4w}

\sf\dfrac{48w^3}{4w}+\dfrac{128w^2}{4w}+\dfrac{4w}{4w}-\dfrac{1}{4w}

48/4 = 12
w^3/w = w^2
So our first term is 12w^2.

128/4 = 32
w^2/w = w
So our second term is 32w.

4w/4w = 1
Anything divided by itself is 1.

-1/4w, this can't be simplified further, so this is our last term.

So we have:

\sf 12w^2+32w+1-\dfrac{1}{4w}
4 0
3 years ago
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