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yulyashka [42]
3 years ago
6

How many different factors does 25 have

Mathematics
2 answers:
viktelen [127]3 years ago
7 0
3? i think so i don’t know if it’s right
Lesechka [4]3 years ago
5 0
Yes, the number 25 does have 3 factors. It’s factors are 1, 5, and 25
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Step-by-step explanation:

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Which fraction is greater than 2/5? 3/10, 7/10, 2/4, 3/6
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An arithmetic sequence is a linear function whose domain is restricted to the set of non-negative integers.
Tom [10]
<h3>What is sequence ?</h3>
  • A sequence is a set of the objects or numbers in a specific order.
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"An arithmetic sequence is a linear function whose domain is restricted to the set of non-negative integers."  

The general form an arithmetic sequence is:

       a_{n} = a_{1} + (n- 1) d

  • The function is linear.
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So, the statement provided is True.

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5 0
2 years ago
F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist
tester [92]

Answer:

(f - g)(x) = x^2 + x-21

(f - g)(10) = 89

(f/g)(x) = \frac{x^2 - 10}{11 - x}

Step-by-step explanation:

Given

f(x) = x^2 - 10

g(x) = 11  - x

Solving (1): (f-g)(x)

(f - g)(x) = f(x) - g(x)

Substitute values for f(x) and g(x)

(f - g)(x) = x^2 - 10 - (11 - x)

Open Bracket

(f - g)(x) = x^2 - 10 - 11 + x

(f - g)(x) = x^2 -21 + x

Reorder

(f - g)(x) = x^2 + x-21

Solving (2): (f-g)(10)

In (1)

(f - g)(x) = x^2 + x-21

So:

(f - g)(10) = 10^2 + 10-21

(f - g)(10) = 100 + 10-21

(f - g)(10) = 89

Solving (3): (f/g)(x)

(f/g)(x) = \frac{f(x)}{g(x)}

Substitute values for f(x) and g(x)

(f/g)(x) = \frac{x^2 - 10}{11 - x}

6 0
3 years ago
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