Answer:
(x+3)(x−2)/(x+7)^2 ≥0 when x ≤ -3 or x ≥ 2.
Step-by-step explanation:
(x+3)(x−2)/(x+7)^2 ≥0
The critical values are (x + 3)(x - 2) = 0.
That is when x = -3 and x = 2.
Set up a table:
x < - 3 x = -3 -3 < x < 2 x = 2 x > 2
x + 3 -ve 0 +ve 0 +ve
x - 2 -Ve -ve -ve 0 +ve
(x+7)^2 +ve +ve +ve +ve +ve
Whole
function + ve 0 - ve 0 +ve
So the function is ≥ 0 when x ≤ -3 and x ≥ 2.
Answer:
x/y
Step-by-step explanation:
The question is badly worded, to the point of being impossible to answer as it is written.
We presume the given point (x, y) is (cos(θ), sin(θ)). The definition of cot(θ) is cos(θ)/sin(θ), so matches x/y with our assumed definitions of x and y.
Answer:
18 cheetos bags, 12 takis bags
Step-by-step explanation:
<u>Assigning:</u>
Let x = number of cheetos bag(s)
Let y = number of takis bag(s)
<u>System of Equations:</u>
x + y = 30
15x + 40y = 750
<u>Solving:</u>
Isolate y in first equation : y = 30 - x
Substitute into second equation:
15x + 40(30 - x) = 750,
15x + 1200 - 40x = 750,
-25x = - 450,
x = 18 cheetos bags
y = 30 - 18 = 12 takis bags
4m + 7 = -3m + 49
4m + 3m = 49 - 7
7m = 42
m = 42/7
m = 6
So, your final answer is 6
Hope this helps!
