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Mnenie [13.5K]
3 years ago
11

The table shows some values of a function of the form y = ax2 + bx + c.

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

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3 years ago
ION 1: BASIC ANNUITIES AND APPLICATIONS [20 MARKS]
DENIUS [597]

Answer:

Find the present and future value of $1000 received every month end for 20  years if the interest rate is J12 = 12%

  • $90,819.42

Find the present value of $10,000 received at the start of every year for 20 years if the interest rate is J1 = 12% p.a. and if the first payment of $10,000 is received  at the end of 10 years.

  • $26,935.64

1.  John is currently 25 years old. He has $10,000 saved up and wishes to deposit  this into a savings account which pays him J12 = 6% p.a. He also wishes to  deposit $X every month into that account so that when he retires at 55, he can withdraw $2000 every month end to support his retirement. He expects to live up till 70 years. How much should he deposit every month into his account?

  • $178.7644 ≈ $178.76

Step-by-step explanation:

there are two ways to solve this question:

  • using the formula for present value of annuity
  • using an annuity table

since this question is about monthly payments, I will use the annuity formula:

PV = payment x {[1 - (1 + r)⁻ⁿ]/r}

PV = 1000 x {[1 - (1 + 0.01)⁻²⁴⁰]/0.01}

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PV = $90,819.42

for the annuity due, we can use an annuity table since payments are annual:

payment $10,000

20 years

12% interest rate

PV annuity due = $10,000 x 8.3658 = $83,658

since the first payment is received 10 years form now, we must determine the PV = $83,658 / (1 + 0.12)¹⁰ = $26,935.64

1)

monthly payment = total amount / discount factor

total amount = monthly payment x discount factor

  • monthly payment = 2,000
  • discount factor = D = {[(1 + r)ⁿ] - 1} / [r(1 + r)ⁿ] = D = {[(1 + 0.005)¹⁸⁰] - 1} / [0.005(1 + 0.005)¹⁸⁰] = 1.45409 / 0.01227 = 118.5032

total amount = $237,006.45

we have to divide John's account in two:

  • the future value of $10,000 = $10,000 x (1 + 6%)³⁰ = $57,434.91
  • so he needs to save an additional $237,006.45 - $57,434.91 = $179,571.54

future value of annuity = monthly payment x {[(1 + r)ⁿ - 1]/ r}

monthly payment = future value /  {[(1 + r)ⁿ - 1]/ r}

  • future value = $179,571.54
  • {[(1 + r)ⁿ - 1]/ r} =  {[(1 + 0.005)³⁶⁰ - 1]/ 0.005} = 1,004.515042

monthly payment = $179,571.54 / 1,004.515042 = $178.7644

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