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Neko [114]
3 years ago
9

Keith is using photo software to enlarge a photograph that is 4 inches by 6 inches to 9 inches by 13.5 inches. What is the scale

factor of the dilation?
Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

2.25

Step-by-step explanation:

The old width of 4 inches became a new width of 9 inches.

Old: 4 in.

New 9 in.

The old length of 6 inches became a new length of 13.5 inches.

Divide the new size by the corresponding old size.

9/4 = 2.25

13.5/6 = 2.25

You see in both cases, the scale factor is 2.25

The scale factor is 2.25

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Answer / Step-by-step explanation:

Before we start to answer this question, it would be nice to understand some basic definition and principles:

Random: This refers to an unpredictable pattern of arrangement.  Without a specific aim or logical procedural pattern.

Uniform Probability distribution: This is a type of probability distribution in which the outcomes of distribution irrespective of the pattern or distance results in equally likely outcomes.

Uniform distribution is one of the widely used distributions although it's one of the simplest ones. The idea behind this distribution is that, unlike the other distributions, the likelihood of the any outcome in the distribution range is the same.

Now that we have a brief knowledge of the key terms within the question, hence, to start answering the question,

(a) Starting with 0 for Alice, Bob can choose any number starting from   1 /  3 . As Alice increases, Bob has to increase his starting point as well. Therefore, after Alice passes  1 /  3 , Bob can start choosing numbers from 0. This creates 2 triangles with sides  1  / 3 . The area of them gives us the probability.

Therefore, : P = 2 ( 1/3 1/3 1/3)

                        = 4/9

(b) We can find the probability of having both the numbers less than  1  / 3 . Then we subtract this probability from 1.

We have: P = 1 - 1/3 . 1/3

                     = 8/9

(c) This is basically impossible as the area of a dot is negligible.

(d) It means that Alice needs to select a number between  1  / 3  and 1.

Therefore: P = 1 - 1 /3

                    = 2 / 3

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Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at
Vinvika [58]
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x  + d 
f '(x) = 3ax^2 + 2bx + c. 
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f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0. 
f(1) = 0 ==> a + b + c + d = 0 
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0. 
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Along these lines, we have the four conditions 
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==> b = 9/32 and c = - 27/32. 
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).
8 0
3 years ago
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