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2 years ago

Do You Understand?Show Me! Explain howyou can use mental mathto add 10 to 47.

Mathematics

1 answer:

Nikitich [7]2 years ago

5 0

Answer:

Well the answer is 57.

Step-by-step explanation:

Okay think about it 10+10 is 20 how do you know this well 1+1=2 and add a zero. So in 10+47 4+1=5 and keep the 7 because the other number is a zero which has no affect on the number unless both numbers are zero.

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if two positive integers P and Q can be expressed as p = a b square and q equals A cube B where A and B being prime numbers then

vodka [1.7K]

P = ab^2
q = a^3 b

p = a * b * b
q = a*a*a * b

Pairing the duplicates we have LCM = a*a*a*b*b = a^3 b^2 answer

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3 years ago

Help pleas brainliest is insured if correct

charle [14.2K]

Answer:

9 units

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2 years ago

Mary invests £12000 in a saving account.

ladessa [460]

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3 years ago

Hank has to drain his pool so repairs can be done on a crack on the bottom. The company coming to fix the pool is scheduled to a

Alik [6]

Answer:

The answer to the question: "Will Hank have the pool drained in time?" is:

Yes, Hank will have the pool drained in time.

Step-by-step explanation:

To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:

Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
Available time = 360 minutes

Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:

Volume of the pool = Deep * Long * Wide
Volume of the pool = 2 m * 10 m * 8 m
Volume of the pool = 160 m^3

Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:

1 m^3 = 264.172 gal

Now, we use a rule of three:

If:

1 m^3 ⇒ 264.172 gal
160 m^3 ⇒ x

And we calculate:

$x = \frac{160 m^{3}*264.172 gal }{1m^{3} }$ (We cancel the unit "m^3)
x = 42267.52 gal

At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:

Time to drain the pool = $\frac{42267.52gal}{130\frac{gal}{min} }$ (We cancel the unit "gallon")
Time to drain the pool = 325.1347692 minutes
Time to drain the pool ≅ 326 minutes (I approximate to the next number because I want to assure the pool is drained in that time)

As we know, Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes.

7 0

2 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

2 years ago

Do You Understand?Show Me! Explain howyou can use mental mathto add 10 to 47.​

Do You Understand?Show Me! Explain howyou can use mental mathto add 10 to 47.