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Vaselesa [24]
3 years ago
12

Do You Understand?Show Me! Explain howyou can use mental mathto add 10 to 47.​

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Well the answer is 57.

Step-by-step explanation:

Okay think about it 10+10 is 20 how do you know this well 1+1=2 and add a zero. So in 10+47 4+1=5 and keep the 7 because the other number is a zero which has no affect on the number unless both numbers are zero.

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If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)
lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

✌ ✌ ✌ ✌

3 0
2 years ago
You are helping a partner in your group with their problem. What mistake did they make solving the system?
Llana [10]
There is no solution
4 0
3 years ago
The Ratio of boys to girls in Martin Middle school is 3/2. what is the percent of the entire school is boys?
Llana [10]

3+2=5

5x=100%

x=20 (divide)

20*3=60

60% are boys, 40% are girls

6 0
3 years ago
Please help me 5-7g-3=
Archy [21]

Answer: −7g+2

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

5 0
3 years ago
Read 2 more answers
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec

therefore

The solution  is t=2.62 seconds

4 0
3 years ago
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