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adell [148]
3 years ago
5

PLS HELP NOOOOOOOOOOOOOOOOWWWWWWWWWWWWWW

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

cant its blocked

Step-by-step explanation:

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What is the approximate length of VU? What is the length of the midsegment parallel to VU?
anastassius [24]

u is at (1,-2)

V is at (-6,-6)

 using distance formula it is about 8.06 long

 so Answer is C

6 0
3 years ago
A video game club charges a fixed annual membership fee of $20 and $2 per video game rented. Let f(n) represent the total annual
djverab [1.8K]
The total cost for video rental, f(n), is the sum of the membership fee and the cost of renting video game. The latter is the product of cost per video game times n video games. The correct equation used to represent the total cost is,
                          f(n) = 20 + 2n
Since the membership is increased by 15, the new equation is,
                          f(n) = 35 + 2n

4 0
3 years ago
Read 2 more answers
Number between 17/4 and V20
Daniel [21]

Answer:

4.485

Step-by-step explanation:

 [divide 17 by 4]

  [  ]

Now, Midpoint of  4.25 and 4.472 =

Number between 4.25 and 4.472 =4.485

Or number between  and  is 4.485.

3 0
3 years ago
How do you do number 20?
LenKa [72]

The answer isnin the pictures

4 0
3 years ago
A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

l - 8/w² = 0 and w - 8/l² = 0

l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

8l = l⁴

l³ = 8

l = ∛8

l = 2

Hence the length of the box is 2 feet

Substituting l = 2 into the function l = 8/w² to get the eidth w

2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

width of the cardboard is 2 ft

Since Volume = lwh

4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
3 years ago
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