To find the value of x, we will have to set the perimeters equal. (2x+4)*4 would be P for the square and (2x+8)*3 would be P for the triangle. We have to set these equal and solve for x. (2x+4)*4=(2x+8)*3 8X+16=6x+24 -6x -16 -6x -16 2x=8 x=4 Now we plug x=4 in for each perimeter. Square: 2(4)+5=13 Triangle: 2(4)+8=16