Answer:
The lower bound is, 
and the upper bound is 
.
Step-by-step explanation:
Let the random variable <em>X</em> follows a normal distribution with mean <em>μ </em>and standard deviation <em>σ</em>.
The the random variable <em>Z, </em>defined as 
is standardized random variable also known as a standard normal random variable. The random variable 
.
The standard normal random variable has a symmetric distribution.
It is provided that 
.
Determine the upper and lower bound as follows:
![P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755](https://tex.z-dn.net/?f=P%28-z%5Cleq%20Z%5Cleq%20z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-P%28Z%5Cleq%20-z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-%5B1-P%28Z%5Cleq%20z%29%5D%3D0.51%5C%5C2P%28Z%5Cleq%20z%29-1%3D0.51%5C%5C2P%28Z%5Cleq%20z%29%3D1.51%5C%5CP%28Z%5Cleq%20z%29%3D0.755)
Use a standard normal table to determine the value of <em>z.</em>
The value of <em>z</em> such that P (Z ≤ z) = 0.755 is 0.69.
The lower bound is, and the upper bound is .
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours. Option A
<h3>Equation</h3>
c(h) = 250 + 200h
s(h) = 300 + 180h
Where,
- number of credit hours taken = h
To have equal tuition in both schools,
equate both function
250 + 200h = 300 + 180h
200h - 180h = 300 - 250
20h = 50
h = 50/20
h = 2.5 hours.
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours.
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Based on the given, there are two ways to know the dimensions of the rectangle. First, by simply drawing the coordinates given in a cartesian coordinate plane, P1(0,6),P2(8,6) by looking at the ordinate the length is 6 units, thru P3 (0,0) and P4 (8,0) and looking at the abscissa, the width is 8 units. The second way is through the distance formula, d=sqrt (X2-X1)2+(Y2-Y1)2. The dimensions are L=8 and W=6
If you triple the ginger, to be able to keep proportion, you would need triple the nutmeg as well.
