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marshall27 [118]
3 years ago
7

Help plzzz real quick on this

Mathematics
2 answers:
AysviL [449]3 years ago
7 0
The parallel lines have the same slope. So we should check the slope from all the options. We will use formula
m = (y₂ - y₁) / (x₂ - x₁)

First Option
(x₁,y₁) = (-8,8)
(x₂,y₂) = (2,2)
Find the slope (m)
m = (y₂ - y₁) / (x₂ - x₁)
m = (2 - 8)/(2 + 8)
m = -6/10
m = -3/5
It has the same slope of -3/5, so it's parallel with the line.

Second Option
(x₁,y₁) = (-5,-1)
(x₂,y₂) = (0,2)
Find the slope (m)
m = (y₂ - y₁) / (x₂ - x₁)
m = (2 + 1) / (0 + 5)
m = 3/5
It doesn't have the same slope, so it's not parallel with the line.

Third Option
(x₁,y₁) = (-3,6)
(x₂,y₂) = (6,-9)
Find the slope (m)
m = (y₂ - y₁) / (x₂ - x₁)
m = (-9 - 6) / (6 + 3)
m = -15/9
m = -5/3
It doesn't have the same slope, so it's not parallel with the line

Fourth Option
(x₁,y₁) = (-2,1)
(x₂,y₂) = (3,-2)
Find the slope (m)
m = (y₂ - y₁) / (x₂ - x₁)
m = (-2 - 1) / (3 + 2)
m = -3/5
It has the same slope of -3/5, so it's parallel with the line.

Fifth Option
(x₁,y₁) = (0,2)
(x₂,y₂) = (5,5)
Find the slope (m)
m = (y₂ - y₁) / (x₂ - x₁)
m = (5 - 2) / (5 - 0)
m = 3/5
It doesn't have the same slope, so it's not parallel with the line.

SUMMARY
The parallel lines are first option and fourth option
Darina [25.2K]3 years ago
3 0
1 and 4. Please give brainliest!
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Goods bought for $800 had to be sold off at a loss of 8% the selling price was​
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800-64=736

Step-by-step explanation:

4 0
3 years ago
WILL GIVE BRAINLIEST What are the like terms in the algebraic expression? Negative a squared b + 6 a b minus 8 + 5 a squared b m
Minchanka [31]

Answer: B

Negative a squared b and 5 a squared b

Step-by-step explanation:

Given that:

Negative a squared b + 6 a b minus 8 + 5 a squared b minus 6 a minus b. That is,

- a^2b + 6ab - 8 + 5a^b - 6a - b

Collecting the like term by rearranging the expression

5a^2b - a^2b + 6ab - 6a - b

The like terms in the expression above are

5a^2b - a^2b.

The correct option is B:

Negative a squared b and 5 a squared b or (-a^2b and 5a^b)

4 0
3 years ago
Read 2 more answers
1 hat cost $12
Ivan

Answer:

he bought 6 hats.

Step-by-step explanation:

im just gonna go through this 1 at a time. starting at 1.

12 + (14x9) = 138

(12x5)+(14x5) = 130

(12x4)+(14x6) = 132

(12x8)+(14x2) = 124

(12x6)+(14x4) = 128

6 0
3 years ago
Rewrite the equation in Ax+By=C form
Ksju [112]

Ax + By = C form of the given equation is –6x + y = –28.

Solution:

Given equation is y – 2 = 6(x – 5).

To write the equation in Ax + By = C format:

y – 2 = 6(x – 5)

y – 2 = 6x – 30

Add 2 on both sides of the equation.

y – 2 + 2 = 6x – 30 + 2

y = 6x – 28

Subtract 6x from both sides of the equation.

y – 6x = 6x – 28 – 6x

y – 6x = –28

Arrange the terms in the equation.

–6x + y = –28

This is in the form of Ax + By = C.

Here A = –6, B = 1 and C = –28.

3 0
3 years ago
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
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