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nydimaria [60]
3 years ago
9

A turtle begins to cross a path. After 3 minutes, the turtle is 2.5 feet from the other edge of the path. After 5 minutes, the t

urtle is 1.5 feet from the other edge of the path. What is the total width of the path in feet?

Mathematics
2 answers:
iragen [17]3 years ago
5 0
The turtle would be moving 0.5 feet every minute. The width of the path is 4 feet.
sergey [27]3 years ago
5 0

Answer:

5.67 feet

Step-by-step explanation:

We are given that a turtle begins to cross a path.

We have to find the total width of the path.

Turtle travel distance in 3 minutes =2.5 feet

Turtle travel distance in 1 minute=\frac{2.5}{3}

Turtle travel distance in 5 minutes form one edge=\frac{2.5}{3}\times 5=\frac{12.5}{3}

The distance of turtle from second edge=1.5 feet

Total width of path

\frac{12.5}{3}+1.5

\frac{12.5+4.5}{3}=\frac{17}{3}

Width of path=5.67 feet.

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Using a system of equations, it is found that the unit prices are:

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For the system:

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From the table, the equations are:

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x + 3y + 3z = 12

Replacing the <u>first equation on the second and the third:</u>

z = 9.25 - 2x - 2y

3x + 4y + z = 14.50

3x + 4y + 9.25 - 2x - 2y = 14.50

x + 2y = 5.25

x = 5.25 - 2y

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x + 3y + 3(9.25 - 2x - 2y) = 12

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5x + 3y = 15.75

Since x = 5.25 - 2y:

5(5.25 - 2y) + 3y = 15.75

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y = \frac{10.5}{7}

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Then:

x = 5.25 - 2y = 5.25 - 2(1.5) = 2.25

z = 9.25 - 2x - 2y = 9.25 - 2(2.25) - 2(1.5) = 1.75

The unit prices are:

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A similar problem, also solved using a system of equations, is given at brainly.com/question/14183076

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