3 years ago

PLZ HELP!!! BRAINLY GUARANTEED

1 answer:

5 0

The answer is D) {x|x≥−3}

The x value’s lowest input in -3, and the function goes to the right, meaning it is greater than -3

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$\boxed{it \: is \: (\frac{(k - 12)}{8} )\times 10^2 \: \: times \: more}$

Step-by-step explanation:

$............................................................... \\ to \: find \: this\: ans :we \: find \: the \: ratio \\ of \: the \: overall \: number \: of \: students \: to \: \\ the \: aveerage \: number \:o f \:students \\ ............................................................... \\ans \: = \frac{overall \: number \: of \: students}{aveerage \: number \:o f \:students} = \frac{k - 12}{8 \times 10^2} \\ therefore \: it \: is \: (\frac{(k - 12)}{8} )\times 10^2 \: \: times \: more.$

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