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ololo11 [35]
2 years ago
6

Solve for x. 1) 6 2)3 3) 63 4) 32

Mathematics
1 answer:
grandymaker [24]2 years ago
4 0

Answer:

djakmakmck

Step-by-step explanation:

i need points

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Alenkinab [10]
Combine like terms then you have your answers
6 0
3 years ago
Read 2 more answers
PLZZZZZZZZ BRAINILEST
vivado [14]

Answer:

Mass

Step-by-step explanation:

"Robin collected data from dropping watermelons of different 'MASS' for the same height"

8 0
2 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
Please help as soon as possible!
AnnZ [28]

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 6) and (x₂, y₂ ) = (8, 4)

m = \frac{4-6}{8-3} = - \frac{2}{5}, hence

y = - \frac{2}{5} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, 4), then

4 = - \frac{16}{5} + c ⇒ c = 4 + \frac{16}{5} = \frac{36}{5}

y = - \frac{2}{5} x + \frac{36}{5} ← equation of line

6 0
2 years ago
Read 2 more answers
The area of rectangular is 64m the length of the pool is 12 m less that the width .The situation can be represented by the equat
beks73 [17]

Answer:

Width = 16 m

Length = 4 m

Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

Area of a rectangle = Length × Width

L = W - 12

Hence:

64 = (W - 12) × W

64 = W² - 12W

W² - 12W - 64 = 0

Factor using

(W + 4)(W - 16) = 0

Width = 16m

Length = W - 12

Length = 16 m - 12 m

= 4 m

6 0
2 years ago
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