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3 years ago

15

1.) Predict how many times you will roll a number less than 3 if you roll a standard number cube 100 times. Round to the nearest

integer, if necessary.
You will roll a number less than 3 about____
times.

2.) you flip a fair coin 28 times. About how many times would you expect heads to appear?

If a fair coin is flipped 28 times then heads should appear about______
times.

1 answer:

MArishka [77]3 years ago

7 0

Step-by-step explanation:

i dont know one. but number to is 14. hope it helps

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If G is the midpoint of FH, FG= 14x + 25 and GH = 73- 2x, find FH

Alenkinab [10]

Given that G is the midpoint of FH, then:
FG=GH
hence;
14x+25=73-2x
solving for x we get:
14x+2x=73-25
16x=48
x=48/16
x=3
therefore the length FG=14x+25 will be:
14*3+25
=67
hence FH will be:
FH=67*2=134

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3 years ago

A class had 11 boys and 9 girls in it. What percent of the class are boys?

scZoUnD [109]

11 divided by 20 = .55

multiply that by 100

55% is your answer

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4 years ago

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Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

4 years ago

Which expression is equivalent to 5g+9+8g+4?

vfiekz [6]

13g+13 sorry if this is wrong

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3 years ago

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The volume of a cone-shaped hole is 1471 ft. If the hole is 9 ft deep, what is the radius of the hole

Ainat [17]

The volume πr^2*height/3=1471

π*r^2=1471/9*3

π*r^2=490.33(I'm rounding all my numbers to the hundredths digit)

r^2=490.33/3.14(taking 3.14 for pi)=about 156.16

r= sqrt 156.16=about 12.5

Again this answer is not precise but I rounded everything to the hundredths digit because pi is never ending. I hope it helped!

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3 years ago