Answer:
Step-by-step explanation:
Given a circle centred at the point P(-4,-6) and passing through the point
R(2,2).
To find its equation, we follow these steps.
Step 1: Determine its radius, r using the distance formula
For point P(-4,-6) and R(2,2)
Step 2: Determine the equation
The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: 
Centre,(h,k)=P(-4,-6)
r=10
Therefore, the equation of the circle is:
Answer:
3p^3 + qp^2 - pq^2 + 3q^3
Step-by-step explanation:
(p²-pq + q²) ( 3p+ 3q)
3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3
3p^3 + qp^2 - pq^2 + 3q^3
The cartesian plane is composed of four quadrants: quadrant I, II, III<span> and IV. Quadrant I has positive x and </span>y axes<span>. Quadrant II has negative </span>x axis<span> and </span>y axis<span>. Quadrant III has both negative x and </span>y axes<span> while quadrant IV has </span>positive x axis<span> and negative </span>y axis<span>. x value refers to the abscissa while y value refers to ordinate. Answer hence is A</span>
Answer:
A 9 ⋅ 1019
B 7.8 ⋅ 106
C 1.45 ⋅ 10−7
D 0.33 ⋅ 10−15
Step-by-step explanation:
A 9 ⋅ 1019
B 7.8 ⋅ 106
C 1.45 ⋅ 10−7
D 0.33 ⋅ 10−15
105% as a decimal would be 1.05 in decimal form
