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Temka [501]
3 years ago
6

Describe the graph of the equation y = 0. Is the equation a function?

Mathematics
2 answers:
omeli [17]3 years ago
8 0
Answer: The equation is not a function.

Explanation: The equation would be considered a function if it was in (y=Mx+b) form. As you showed here we have the (mx) part and not the (b) which would be the slope.
liubo4ka [24]3 years ago
4 0

Answer: B. horizontal line; yes

Use the slope-intercept form to find the slope and y-intercept.

Slope:  

0

y-intercept:  

(0,0)

Yes it is a function. It is a horizontal line.  

Every point on this line is of the form (x,4) where x can be any number you want. The y coordinate is fixed at 4 and cannot change. Two points on this line are (0,4) and (1,4). The horizontal line goes through 4 on the vertical y axis.  

Why is it a function? Because it is impossible to draw a vertical line through more than one point on the graph of y = 4. The graph passes the vertical line test. Put another way, for any x input, there is exactly one y output.  

Side Note: y = 4 is the same as y = 0x+4. Note how its in the form y = mx+b

m = 0 is the slope

b = 4 is the y intercept

Step-by-step explanation: A. vertical line; yes

horizontal line; yes

Yes! Horizontal line represents a function y = f(x)

(1):Firstly, lets understand a function. For a function to be defined, we have a set of independent variables(inputs) (Domain), a set of dependent variables (outputs) (Codomain). And a relation between the variables.

(2): Each input in X must be related to exactly one output in Y. Or else it won't represent a function.. like in the following image.. y is a function of x.Because each element ofX has one& only one image in Y

C. vertical line; no

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Solve the system of equations given below.<br> y - 15 = 3<br> -2.1 + 5y = -3
EastWind [94]

Answer:

1) y=18

2)y=-0.18

Step-by-step explanation:

1) y-15=3. Add 15 on both sides.

y=18

2)-2.1+5y=-3. Add 2.1 on both sides

5y=-0.9. Divide 5 on both sides

y=-0.18

3 0
3 years ago
I need help please. Thanks!
Karolina [17]

Answer:

A

Step-by-step explanation:

We are given the function f and its derivative, given by:

f^\prime(x)=x^2-a^2=(x-a)(x+a)

Remember that f(x) is decreasing when f'(x) < 0.

And f(x) is increasing when f'(x) > 0.

Firstly, determining our zeros for f'(x), we see that:

0=(x-a)(x+a)\Rightarrow x=a, -a

Since a is a (non-zero) positive constant, -a is negative.

We can create the following number line:

<-----(-a)-----0-----(a)----->

Next, we will test values to the left of -a by using (-a - 1). So:

f^\prime(-a-1)=(-a-1-a)(-a-1+a)=(-2a-1)(-1)=2a+1

Since a is a positive constant, (2a + 1) will be positive as well.

So, since f'(x) > 0 for x < -a, f(x) increases for all x < -a.

To test values between -a and a, we can use 0. Hence:

f^\prime(0)=(0-a)(0+a)=-a^2

This will always be negative.

So, since f'(x) < 0 for -a < x < a, f(x) decreases for all -a < x < a.

Lasting, we can test all values greater than a by using (a + 1). So:

f^\prime(a+1)=(a+1-a)(a+1+a)=(1)(2a+1)=2a+1

Again, since a > 0, (2a + 1) will always be positive.

So, since f'(x) > 0 for x > a, f(x) increases for all x > a.

The answer choices ask for the domain for which f(x) is decreasing.

f(x) is decreasing for -a < x < a since f'(x) < 0 for -a < x < a.

So, the correct answer is A.

3 0
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Answer:

i have no idea girl or boy

Step-by-step explanation:

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