Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Answer:
14 units
Step-by-step explanation:
12-(-2)=14
1. x^15
2. m^40
3. v^7/2
4. k^4
5. 1/x^14
6. 1/r^3/2
7. b^25
8. h^2
9. m^3n^1/7
10. x^12
11. 1/g^37
12. 1/100m^6
13. j^6/216
14. 1/125f^3
15. 3z^1/2
16. 1/100m^6
17. j^6/216
18.1/81d^20
19. 1
20. g^1/2 r^3
21. 16a^11
22. m^16n^21
23. 1
24. 1/y^10x^6
25. 343s^10/t^17/2
26.n^17/2 /m^10/2
27. 729/b^24c^9
28. 20y^2/x^33
Answer:
x = 80, y = 122
Step-by-step explanation:
I got this equation by using vertical angles to create a complimentary angle pair (they sum to 90 degrees).
3/4x+2/5x-2=90°,
23/20x - 2=90°,
23/20x = 92°,
92/(23/20)
20/(1/4)
20(4)
= 80.
Since the angles are a linear pair on the left side(they sum to 180 degrees). Just subtract 180 from 3/4x-2 and substitute x into the expression.
180-(3/4(x)-2), 180-3/4(80)+2 = 120+2 = 122
In this case, you first need to think about what is the formula for the circumference of a circle. <span>The formula for the circumference of a circle is 2 * PI * r, where r is the radius of the circle, and PI is the mathematical constant approximately equal to 3.14.
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