The Lagrangian is

with partial derivatives (set equal to 0)





Case 1: If
, then

Then


So we have two critical points,
and 
Case 2: If
, then in the first equation we get

and from the third equation,

Then


but there are no real solutions for
, so this case yields no additional critical points.
So at the two critical points we've found, we get extreme values of
(min)
and
(max)
Answer:
n = s/180 +2
Step-by-step explanation:
180(n-2)=s
Distribute
180n - 360 =s
Add 360 to each side
180n -360+360 = s+360
180n = s+360
Divide each side by 180
180n/180 = s/180 + 360/180
n = s/180 +2
rad 128 can be broke into 64*2
square root of 64 is 8, times -5,
which leaves -40rad2
So b is the correct answer