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natulia [17]
2 years ago
10

A submarine on the surface of the ocean descended at a rate of 7 feet per second for 2 minutes. Then it ascended at a rate of 4

feet per second for 3 minutes, Finally, it descended at a rate of 9 feet per second for 5 minutes.
What was the final elevation of the submarine?
Mathematics
2 answers:
kotykmax [81]2 years ago
8 0

Answer:

4,260 feet below sea level (-4,260 feet)

Step-by-step explanation:

The submarine starts at sea level which should be 0 for elevation. And descending 7 feet per second for 2 minutes which means it went down 840 feet ( 7x60x2). Then 4 feet per second for 3 minutes which is 720 feet (4x60x3). Lastly 9 feet per second for 5 minutes which is 2,700 feet (9x60x5). Then you add up those three totals, 840 + 720 + 2,700 = 4,260. So the elevation is -4,260 feet, or 4,260 feet below sea level

aleksandr82 [10.1K]2 years ago
4 0

Answer:

I believe the answer is 2,820 feet.

Step-by-step explanation:

First, you would need to multiply 60 by however many minutes to see how many seconds there are.

Second, multiply the number of feet by the seconds you found from the first step.

Lastly, add together the two descending part. Then subtract it from the ascending part.

  1. 7 x 120 = 840
  2. 4 x 180 = 720
  3. 9 x 300 = 2700
  4. 2,700 + 840 = 3,540 - 720 = 2,820 is the answer
<h2>MARK ME BRAINLIEST PLEASE!!!!!!</h2>

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Nataly_w [17]

Answer:

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Step-by-step explanation:

In both questions you want to get the x alone.

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2 years ago
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romanna [79]

Answer: To get 24

Step-by-step explanation

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Step-by-step explanation:

8 0
3 years ago
If joe has12 checkers and 5/6 of them are red how many are red
natta225 [31]

Given:

The number of checkers is 12.

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Multiply 5/6 and 12 to find the number of red.

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