Question

A submarine on the surface of the ocean descended at a rate of 7 feet per second for 2 minutes. Then it ascended at a rate of 4 feet per second for 3 minutes, Finally, it descended at a rate of 9 feet per second for 5 minutes.
What was the final elevation of the submarine?

Answer 1

Answer:

4,260 feet below sea level (-4,260 feet)

Step-by-step explanation:

The submarine starts at sea level which should be 0 for elevation. And descending 7 feet per second for 2 minutes which means it went down 840 feet ( 7x60x2). Then 4 feet per second for 3 minutes which is 720 feet (4x60x3). Lastly 9 feet per second for 5 minutes which is 2,700 feet (9x60x5). Then you add up those three totals, 840 + 720 + 2,700 = 4,260. So the elevation is -4,260 feet, or 4,260 feet below sea level

Answer 2

Answer:

I believe the answer is 2,820 feet.

Step-by-step explanation:

First, you would need to multiply 60 by however many minutes to see how many seconds there are.

Second, multiply the number of feet by the seconds you found from the first step.

Lastly, add together the two descending part. Then subtract it from the ascending part.

1. 7 x 120 = 840
2. 4 x 180 = 720
3. 9 x 300 = 2700
4. 2,700 + 840 = 3,540 - 720 = 2,820 is the answer

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