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Leviafan [203]
3 years ago
6

What is the square root of -1? -j. -1

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

Its not a real number for the square roots of negative number

its not possible... \sqrt{-4} = -2 x -2   no...   2 x 2   no..... -2 x 2 yea but thats not square root anymore...

Step-by-step explanation:

Give me brainliest!!!

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Determine the ordered pair that satisfies the equation, 5x + 2y = 7.
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Step-by-step explanation:

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3 years ago
Integration of (cosec^2 x-2005)÷cos^2005 x dx is
kondor19780726 [428]
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then, 
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.

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