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nydimaria [60]
3 years ago
10

Find the area of this shape. Correct answer will Brainliest

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

As shown in picture, this is a trapezoid.

The area of a trapezoid is calculated by:

A = (base1 + base2) x height x (1/2)

To work out A, we need to find out base1, base2, and height.

base1  = YZ = \sqrt{(Zx - Yx)^{2} + (Zy - Yy)^{2} } = \sqrt{(5 - 2)^{2} + (5 - 5)^{2} } = 3

base2 = XW =\sqrt{(Wx - Xx)^{2} + (Wy - Xy)^{2} } = \sqrt{(8 - 1)^{2} + (1 - 1)^{2} } = 7

Otherwise, the height (distance between base1 and base2) is 4 as shown in picture.

=> A = (3 + 7) x 4 x (1/2) = 20

Hope this helps!

:)

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Find the common difference for the sequence below. 1/4, 5/16, 3/8,..
vredina [299]

Answer:

the common difference of the sequence is (\frac{1}{16})

Step-by-step explanation:

A sequence of numbers is said to be in arithmetic progression of each term of the sequence has same common difference.

Now, here first term a1 = 1/4

Second term a2 = 5/16

Third term a3 = 3/8

Now, Common difference (d) = a2 - a1 = a3 - a2

Now, a2 - a1 = \frac{5}{16}  - \frac{1}{4}  = \frac{5 - 4}{16}  = \frac{1}{16}

Now, a3 - a2 =  \frac{3}{8}  - \frac{5}{16}  = \frac{6 - 5}{16}  = \frac{1}{16}

Hence, the common difference of the sequence is (\frac{1}{16})

5 0
3 years ago
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
(-3+x) divided by 2= negative one half
Arlecino [84]

Answer:

are u trying to find x?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Diego had $21.32 and gave $9.50 to Elena. How much did he have left?
Charra [1.4K]

Answer:

11.82

Step-by-step explanation: I know this because 21.32-9.50= 11.82

7 0
3 years ago
What is the surface area of the prism in square inches?
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<h2>add 60+168+276+304 and you get 810 square inches then add 3+14+8 and equals 835.</h2>
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