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Leviafan [203]
3 years ago
6

Is 8.27 rational or irrational?

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
3 0

Answer:

Rational

Step-by-step explanation:

A terminating decimal is a rational number.

A repeating decimal is a irrational number.

Since 8.27 terminates, it is rational.

LUCKY_DIMON [66]3 years ago
3 0

Answer:

it is a rational number

Step-by-step explanation:

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Mia wants to borrow £6000 and repay it, with interest, after two years. she sees two offers for loans: offer 1 compound interest
AURORKA [14]

Answer:

she is wrong, offer 2 results in lower interests

Step-by-step explanation:

total amount paid if offer 1 is accepted:

$6,000 x (1 + 3%)² = $6,000 x 1.0609 = $6,365.40

she will pay $365.40 in interests

total amount paid if offer 2 is accepted:

($6,000 x 1.01) x 1.05 = $6,060 x 1.05 = $6,363

she will pay $363 in interests

Compounding interest refers to interest that earns more interest itself, e.g. in the first offer, the $180 of interests charged for the first year will earn $5.40 in extra interests. While offer 2 only charges $60 in interests during the first year which will in turn earn $3 of interests. The difference between both offers is that interest charges in offer 1 earn more interests than the interest in offer 2 = $5.40 - $3 = $2.40

4 0
3 years ago
HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️
Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0
1 year ago
If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?
Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

f(x)=x+7

g(x)=\frac{1}{x-13}

We have to find the domain of fog(x).

fog(x)=f(g(x))

fog(x)=f(\frac{1}{x-13})

fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0
2 years ago
Read 2 more answers
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the dif
rodikova [14]

Answer:

60men 40 women.... but I ain't sure

4 0
3 years ago
Complete the proof by providing the missing statement and reasons
Lisa [10]

Answer:

In triangle SHD and triangle STD.

\overline{SD} \perp \overline{HT}          [Side]

Since, a line is said to be perpendicular to another line if the two lines intersect at a right angle.

⇒ \angle SDH = \angle SDT = 90^{\circ}

\overline{SH} \cong \overline{ST}       [leg]               [Given]

Reflexive property states that the value is equal to itself.

\overline{SD} \cong \overline{SD}       [Leg]       [Reflexive property]

HL(Hypotenuse-leg) theorem states that any two right triangles that have a congruent hypotenuse and a corresponding congruent leg are the congruent triangles.


then, by HL theorem;

\triangle SHD \cong \triangle STD                       Proved!



6 0
3 years ago
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