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kari74 [83]
2 years ago
10

Help would help please :) auestion in attacment

Mathematics
1 answer:
Leya [2.2K]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

Ravi will get:

50,000x(2/(2+3))=50,000x(2/5)=20,000

Rani will get:

50,000x(3/(2+3))=50,000x(3/5)=30,000

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Josh had $10 more than Carly, so he gave Carly half of his money. Then Carly had more money than josh, so she gave Josh $4. Then
DedPeter [7]

each person starts with $8.

<u>Step-by-step explanation:</u>

Here we have , Josh had $10 more than Carly, so he gave Carly half of his money. Then Carly had more money than josh, so she gave Josh $4. Then they both had $13. We need to find  How much money did each person start  . Let's find out:

Suppose Carly had $x ,  Josh had $10 more than Carly i.e. $(x+10), so he gave Carly half of his money i.e.

⇒ \frac{x+10}{2} ,Now , Josh have $\frac{x+10}{2}  & Carly have x + \frac{x+10}{2} .

Then Carly had more money than josh, so she gave Josh $4 . So ,

Josh now have $(4+\frac{x+10}{2})  and  Carly now have $(x+\frac{x+10}{2} -4) . Since both are equal :

⇒  (x+\frac{x+10}{2} -4) = (4+\frac{x+10}{2})

⇒  x-4 = 4

⇒  x=8

Therefore , each person starts with $8.

8 0
3 years ago
Jenna sells apples and pears. If 20 apples and 60 pears re sold every hour, there will be 80 pears when all the apples are sold.
lutik1710 [3]

Answer:

There are 1,360 pears.

Step-by-step explanation:

Suppose that there are P pears and A apples.

We know that:

"If 20 apples and 60 pears are sold every hour, there will be 80 pears when all the apples are sold."

Suppose that all of these are sold after N hours, then:

20*N = A

80*N = P - 80

We also know that:

"if 60 apples and 20 pears are sold every hour, there will be 400 pears when all the apples are sold."

60*N = A

20*N = P - 400

Then we have four equations:

20*N = A

80*N = P - 80

60*N = A

20*N = P - 400

From the first one and the second one, we get:

20*N = A = 20*N = P - 400

A = P - 400

Now we have 3 equations:

80*N = P - 80

60*N = A

A = P - 400

Now we can just replace the third equation into the second one, then we get:

60*N = A = P - 400

Now we have two equations:

80*N = P - 80

60*N = P - 400

Now, remember that we want to find the number of pears, so we want to find the value of P.

To do it, we can take the quotient of the two equations, so we get:

(80*N)/(60*N) = (P - 80)/(P - 400)

8/6 = (P - 80)/(P - 400)

Now we can solve this for P

(8/6)*(P - 400) = P - 80

(8/6)*P - (8/6)*400 = P - 80

(8/6)*P - P = (8/6)*400 - 80

(2/6)*P = (8/6)*400 - 80

P = (6/2)*( (8/6)*400 - 80 )

P = 3*( (8/6)*400 - 80 ) = 1,360

There are 1,360 pears.

3 0
2 years ago
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
Lelu [443]
Hello : 
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2  +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
4 0
3 years ago
Read 2 more answers
25x2 + 5x
poizon [28]

Answer:

option C: 5x+1

Explaination:

take 5x common and simplify

3 0
2 years ago
Help pls!!!
SVEN [57.7K]

Answer:

an = -6n + 5.

Step-by-step explanation:

This is an arithmetic sequence with first term a1 = -1 and common difference d = -6

an = a1 + d(n-1)

an = -1 + -6(n - 1)

an = -1 -6n + 6

an = -6n + 5.

3 0
3 years ago
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